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2 years ago

Write 12/root2 + root18 in the form broot2 where b is an interger

1 answer:

katrin2010 [14]2 years ago

5 0

$\dfrac{12}{\sqrt 2} + \sqrt{18}\\\\\\=\dfrac{12 + \sqrt{18 \times 2}}{\sqrt 2}\\\\\\=\dfrac{12+\sqrt{9 \times 4}}{\sqrt 2}\\\\\\=\dfrac{12+3 \times 2}{\sqrt 2}\\\\\\=\dfrac{18}{\sqrt 2}\\\\\\=\dfrac{18\sqrt 2}{\left(\sqrt 2\right)^2}\\\\\\=\dfrac{18\sqrt 2}2\\\\\\=9\sqrt 2$

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Orlov [11]

Answer:

Option A

Step-by-step explanation:

We need to solve out ,

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2 years ago

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Murljashka [212]

Answer:

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