Is there more to questions. you can solve it with little info
Answer:
Step-by-step explanation:
1) 
= 50 + (-9*8) *1
= 50 - 9.8
= 40.2 m/s
2) The acceleration of the ball at its maximum height equals to the force of gravity. -9.8 m/s²
3) The velocity at its top of the path:When the ball is thrown straight up, its velocity keeps on decreasing due the pull of gravity which pulls it towards the ground. So, the velocity at the top of its path is zero.
Answer:
1. $3.00+42=$3.42
2. 4 Dimes , 2 Pennies
Step-by-step explanation:
2. 4 Dimes = 40 cents , 2 pennies = 2 cents
1. Add up 3.00+42 and that is how you could get the answer for number 1 .
Answer:
![6^{\frac{1}{5} }=\sqrt[5]{6}](https://tex.z-dn.net/?f=6%5E%7B%5Cfrac%7B1%7D%7B5%7D%20%7D%3D%5Csqrt%5B5%5D%7B6%7D)
![6^{\frac{7}{5} }=\sqrt[5]{6^7}](https://tex.z-dn.net/?f=6%5E%7B%5Cfrac%7B7%7D%7B5%7D%20%7D%3D%5Csqrt%5B5%5D%7B6%5E7%7D)
![6^{\frac{1}{6} }=\sqrt[6]{6}](https://tex.z-dn.net/?f=6%5E%7B%5Cfrac%7B1%7D%7B6%7D%20%7D%3D%5Csqrt%5B6%5D%7B6%7D)
![7^{\frac{1}{2} }=\sqrt[2]{7}](https://tex.z-dn.net/?f=7%5E%7B%5Cfrac%7B1%7D%7B2%7D%20%7D%3D%5Csqrt%5B2%5D%7B7%7D)
![7^{\frac{5}{2} }=\sqrt[2]{7^5}](https://tex.z-dn.net/?f=7%5E%7B%5Cfrac%7B5%7D%7B2%7D%20%7D%3D%5Csqrt%5B2%5D%7B7%5E5%7D)
![6^{\frac{9}{2} }=\sqrt[2]{6^9}](https://tex.z-dn.net/?f=6%5E%7B%5Cfrac%7B9%7D%7B2%7D%20%7D%3D%5Csqrt%5B2%5D%7B6%5E9%7D)
Step-by-step explanation:
A radical is the root operation for n roots such as square root or cuberoot in the form
. A fraction exponent
can be converted to the radical form.
![6^{\frac{1}{5} }=\sqrt[5]{6}](https://tex.z-dn.net/?f=6%5E%7B%5Cfrac%7B1%7D%7B5%7D%20%7D%3D%5Csqrt%5B5%5D%7B6%7D)
![6^{\frac{7}{5} }=\sqrt[5]{6^7}](https://tex.z-dn.net/?f=6%5E%7B%5Cfrac%7B7%7D%7B5%7D%20%7D%3D%5Csqrt%5B5%5D%7B6%5E7%7D)
![6^{\frac{1}{6} }=\sqrt[6]{6}](https://tex.z-dn.net/?f=6%5E%7B%5Cfrac%7B1%7D%7B6%7D%20%7D%3D%5Csqrt%5B6%5D%7B6%7D)
![7^{\frac{1}{2} }=\sqrt[2]{7}](https://tex.z-dn.net/?f=7%5E%7B%5Cfrac%7B1%7D%7B2%7D%20%7D%3D%5Csqrt%5B2%5D%7B7%7D)
![7^{\frac{5}{2} }=\sqrt[2]{7^5}](https://tex.z-dn.net/?f=7%5E%7B%5Cfrac%7B5%7D%7B2%7D%20%7D%3D%5Csqrt%5B2%5D%7B7%5E5%7D)
![6^{\frac{9}{2} }=\sqrt[2]{6^9}](https://tex.z-dn.net/?f=6%5E%7B%5Cfrac%7B9%7D%7B2%7D%20%7D%3D%5Csqrt%5B2%5D%7B6%5E9%7D)