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3 years ago

Help WiTh tHis ThIng PleAsE dies lol

Mathematics

2 answers:

Leviafan [203]3 years ago

8 0

Answer:

see explanation

Step-by-step explanation:

Since it is a balance then both sides are the same, that is equal.

The 4 weights represented by circles can be written as 4w, then

4w = 25 ← equation representing the situation

Divide both sides by 4 to find w

w = 25 ÷ 4 = 6.25 ← the weight of 1 circle

sweet-ann [11.9K]3 years ago

8 0

The correct answer is B

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Ill give brainliest and 5 stars and thanks if answer this what is the result of substituting for y in the bottom equation

GREYUIT [131]

We have two set of solutions , ( $\frac{\sqrt{29} }{2}$ , $\frac{\sqrt{29} }{2}$ + 3 ) , ( - $\frac{\sqrt{29} }{2}$ + 3 , - $\frac{\sqrt{29} }{2}$ + 3).

<u>Step-by-step explanation:</u>

We have , the following equations:

$y = x+3$ and $y = x^{2} +2x -4$ . Let's substitute value of y in bottom equation:

⇒ $y = x^{2} +2x -4$

⇒ $x+3 = x^{2} +2x -4$

⇒ $x^{2} +x -7= 0$

Roots of quadratic equation are given by: a = 1, b= 1 , c = -7

$x = \frac{\sqrt{b^{2}-4ac} }{2a}$

⇒ $x = \frac{\sqrt{b^{2}-4ac} }{2a}$

⇒ $x = \frac{\sqrt{1^{2}-4(1)(-7)} }{2(1)}$

⇒ $x = \frac{\sqrt{29} }{2}$ which is actually x = ± $\frac{\sqrt{29} }{2}$ .

We know that $y = x+3$ ,

⇒ y = ± $\frac{\sqrt{29} }{2}$ + 3.

We have two set of solutions , ( $\frac{\sqrt{29} }{2}$ , $\frac{\sqrt{29} }{2}$ + 3 ) , ( - $\frac{\sqrt{29} }{2}$ + 3 , - $\frac{\sqrt{29} }{2}$ + 3).

5 0

3 years ago

Y=−3(2.5)x

Hoochie [10]

Answer:

1. The equation represent an exponential decay

2. The rate of the exponential decay is -3×2.5ˣ·㏑(2.5)

Step-by-step explanation:

When a function a(t) = a₀(1 + r)ˣ has exponential growth, the logarithm of x grows with time such that;

log a(t) = log(a₀) + x·log(1 + r)

Hence in the equation -3 ≡ a₀, (1 + r) ≡ 2.5 and y ≡ a(t). Plugging in the values in the above equation for the condition of an exponential growth, we have;

log y = log(-3) + x·log(2.5)

Therefore, since log(-3) is complex, the equation does not represent an exponential growth hence the equation represents an exponential decay.

The rate of the exponential decay is given by the following equation;

$\frac{dy}{dx} =\frac{d(-3(2.5)^x)}{dx} = -\frac{d(3\cdot e^{x\cdot ln(2.5)})}{dx} = -3 \times 2.5^x\times ln(2.5)$