Use the formula h(t) = -16t^2 + vt + s,
where t = time in air,
v = starting upward velocity,
s = the objects starting height.
from ground (s), the starting height is 0,
the ball's initial velocity (v) 25 feet per second
Solve:
v - 16t^2 + (25)t + 0
= -16t^2 + 25t. 0
Factor:
= -16t^2 + 25t
Find GCF:
0 = -16t^2 + 25t
Divide both sides by (t)
t(-16 + 25) = 0
t = 0; -16 + 25 = 0
Now Subtract 25 from both sides of equation:
-16 = -25
divide both sides by -16 to get -25/-16
= 1.56
Rounds to 1.60, or 1.6
Answer: 1.6 Seconds it will take for soccer ball to hit the ground again.
First part of the Equation: Answer: 9.8Ft. Soccer ball will reach at maximum height.
Hope that helps!!!! : )
Answer:
B
Step-by-step explanation:
Since x is in an absolute value, we know that no matter what value we put in for x, the result will always be positive. B fits this description.
This would be modeled by a translation 1 unit down and a 270° clockwise rotation.
Each of these points has the x and y values switched, with the y value one less than that of the preimage and negated. Taking one off the y-value is a translation 1 down; negating the y and switching it and x is a 270° clockwise rotation.
The answer is 3/4 because if u count it up it equals 36/48 and then u just have to simplify
