Answer:
Step-by-step explanation:
Given data
Total units = 250
Current occupants = 223
Rent per unit = 892 slips of Gold-Pressed latinum
Current rent = 892 x 223 =198,916 slips of Gold-Pressed latinum
After increase in the rent, then the rent function becomes
Let us conside 'y' is increased in amount of rent
Then occupants left will be [223 - y]
Rent = [892 + 2y][223 - y] = R[y]
To maximize rent =
Since 'y' comes in negative, the owner must decrease his rent to maximixe profit.
Since there are only 250 units available;
![y=-250+223=-27\\\\maximum \,profit =[892+2(-27)][223+27]\\=838 * 250\\=838\,for\,250\,units](https://tex.z-dn.net/?f=y%3D-250%2B223%3D-27%5C%5C%5C%5Cmaximum%20%5C%2Cprofit%20%3D%5B892%2B2%28-27%29%5D%5B223%2B27%5D%5C%5C%3D838%20%2A%20250%5C%5C%3D838%5C%2Cfor%5C%2C250%5C%2Cunits)
Optimal rent - 838 slips of Gold-Pressed latinum
Let the number of comic books be X
if we add 14 to X = 24
so we will find the value of X to get half initial number of comic books William had.
14+X=24
X=24-14
X=10
so the total innitial number of comic books William had is 10+10=20 books.
The mean is the average of the numbers.
It is easy to calculate: add up all the numbers, then divide by how many numbers there are.
Let the number of sit-ups you have to do Sunday be x. Then the sum of all sit-ups is
100+65+120+150+90+0+x=525+x.
The number of days is 7.
Thus, the mean is
You know that the mean number of sit-ups per day is 100, equate these two means and solve the equation:
Answer: 175 sit-ups
X - number of the adults, y - number of children;
The system is:
10 x + 6 y = 3292
x + y = 350 => y = 350 - x
----------------------
10 x + 6 * ( 350 - x ) = 3292
10 x + 2100 - 6 x = 3292
4 x = 3292 - 2100
4 x = 1192
x = 1192 : 4
x = 298
y = 350 - 298
y = 52
Answer:
There were 598 adults and 52 children at the showing.
Answer:
Step-by-step explanation:
we know that
The compound interest formula is equal to
where
A is the amount that she will repay
P is the amount borrowed
r is the rate of interest in decimal
t is Number of Time Periods
n is the number of times interest is compounded per year
in this problem we have
substitute in the formula above
Find out the interest
substitute the values
