Answer:
If you call the smaller integer "x" and the greater integer "y", then:
x+y=3x-11 The sum of the two is 11 less than 3 times the smaller
y=x+1 Because they are consecutive, the greater must be 1 more than the smaller
Then you can solve for x:
x+(x+1)=3x-11 Substitute x+1 for y
2x+1=3x-11 Combine like terms
2x+12=3x Add 11 to both sides
12=x Subtract 2x from both sides
The smaller integer is 12, thus the greater integer is 1 more or 13.
Check:
12+13=3(12)-11
25=36-11
25=25 Yes, so the integers are 12 and 13
Step-by-step explanation:
thats pretty much it
Answer:
x² - (4 ≤ 5)
Step-by-step explanation:
(I have x representing the number that is squared, it might be a different letter on your options, but regardless it will be the same general answer. You also may not need the parentheses around the 4 ≤ 5)
Difference means subtraction so we know that the second number/group of numbers will be subtracted from the first that is listed.
Next, if you are squaring any number it's going to have the little 2 to the right of it. That's what that means.
Then, we look at that last bit. <em>"Four is less than or equal to five."</em> This means exactly how it sounds. To write this we need the symbol ≤. This symbol means less than or equal to. You would would but the 4 in front and the 5 in back to get 4 ≤ 5.
Now we just put it together. It tells us that 4 ≤ 5 is being subtracted from a number squared. So this means that a number squared needs to be first, and because difference means subtraction, we would subtract 4 ≤ 5 from that. A number squared can be represented by any letter variable, but for this example, I will use x.
This leaves you with x² - (4 ≤ 5)
I hope this helped :)
Answer:
Step-by-step explanation:
Given equation:
![\sqrt[3]{8x^5} - \sqrt[4]{256y^3}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B8x%5E5%7D%20-%20%5Csqrt%5B4%5D%7B256y%5E3%7D)
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Answer:
Addition Property
Step-by-step explanation:
Added 4 on both sides to equate the solution
Answer:
4 I believe
Step-by-step explanation:
