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2 years ago

If 1=3 2=3 3=5 4=4 5=4, then 6=?

Mathematics

1 answer:

jeyben [28]2 years ago

7 0

Answer:

six equal to eight?????

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3 less than the quotient of 20 and x

UkoKoshka [18]

It would be (20/x) -3

3 0

3 years ago

F(x) = 4/x-9 g(x)=4/x + 9 find f(g(x))

Alenkinab [10]

Hello,

$f(x)= \dfrac{4}{x-9} \\

g(x)= \dfrac{4}{x+9} \\

f(g(x))=f( \dfrac{4}{x+9} )\\

= \dfrac{4}{ \dfrac{4}{x+9}-9} \\

= \dfrac{4(x+9)}{4-9x-81} \\

=- \dfrac{4x+36}{77x+9x} 


$

6 0

3 years ago

Prime factorazation of 13

Neporo4naja [7]

Answer:

13 = 13

Step-by-step explanation:

13 is a prime, so 13 is its only prime factor.

4 0

2 years ago

Landon scored an 85% on his test. If he got 34 problems correct, how many were on the test?

Sergeu [11.5K]

Answer:

There are 40 problems on the test

Step-by-step explanation:

Let p = the number of problems on the test

The number of problems on the test times the percent correct is the number correct

p * 85% = 34

p * .85 = 34

Divide each side by .85

p * .85/.85 = 34/.85

p = 40

There are 40 problems on the test

6 0

2 years ago

Select interior, exterior, or on the circle (x - 5) 2 + (y + 3) 2 = 25 for the following point. (2, 3)

lozanna [386]

Standard equation of a circle: (x-h)² + (y-k)² = r² where (h, k) is the center and r is the radius. In the case of our equation here, (x-5)² + (y+3)² = 25, we can conclude that our circle has a center at (5, -3) and a radius of 5 units.

We can use the distance formula with the center (5, -3) and our point (2, 3) to see how far away they are...if the distance between them is less than the radius of the circle, it is on the interior. If it's equal, it's on the circle. If it's greater, it's on the exterior.

Distance = $\sqrt{(y_2-y_1)^2+(x_2-x_1)^2}$

Distance = $\sqrt{(-3-3)^2+(5-2)^2}$

Distance = $\sqrt{(-6)^2+3^2}$

Distance = $\sqrt{36+9}$

Distance = $\sqrt{45}\approx6.7082$

$6.7082>5,\ so\ (2,3)\ is\ on\ the\ \boxed{exterior}$

8 0

3 years ago