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jek_recluse [69]
2 years ago
5

Two different ratios equivalent to 6:9

Mathematics
2 answers:
ycow [4]2 years ago
7 0

Answer:

Following are ratios equivalent to 6:9

Step-by-step explanation:

1) 12:18

2)24:36

3)2:3

4)20:30

5)10:15

Lerok [7]2 years ago
6 0

Answer: 2:3 and 12:18

Step-by-step explanation: Find the multiples of 6 and 9

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50, 40<br> What’s the GCF of these numbers
dexar [7]

Answer:

10

Step-by-step explanation:

40=2 x 2 x 2 x 5

50=2 x 5 x 5

therefore, GFC = 2x5

GFC= 10

3 0
3 years ago
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Gerald has a punch bowl in the shape of a hemisphere as shown below.
zmey [24]

The closest to the maximum number of cups the punch bowl can hold is 30

<h3>How to determine the number of cups?</h3>

The given parameters are:

1 cup = 15 cubic inches

Diameter of bowl, d = 12 inches

The radius is the half of the diameter.

So, we have:

r = 6

The volume of the bowl is then calculated using:

V = \frac{2}{3}\pi r^3

This gives

V = \frac{2}{3}\pi * 6^3

Evaluate

V = 452.16

The maximum number of cups is then calculated using:

Cups = 452.16/15

Evaluate

Cups = 30.1444

Approximate

Cups = 30

Hence, the closest to the maximum number of cups the punch bowl can hold is 30

Read more about volumes at:

brainly.com/question/1972490

#SPJ1

6 0
2 years ago
HELP ME ASAP PLEASEEEEEEE
Vlad [161]

Answer: a) about 450

Step-by-step explanation:

50 multiplied by 9 is 450 and its asking for an approximate so it would be anything near 450

3 0
2 years ago
9x - 7x2 +4x2 - x + 4x3 - 3x2
Anna35 [415]

Answer:

The answer to your question is:    4x³ - 6x² + 8x

Step-by-step explanation:

see the picture  

3 0
3 years ago
The rule below shows how to find the position of an object thrown upward with initial velocity of 15 feet per second. Which answ
nekit [7.7K]

Here we're applying a basic physics rule for vertical motion where the only pull on the object is gravity.


This rule has the form


h(t) = h + v t + (1/2)a*t^2

o o


To adapt this rule to this particular question replace h with 0, as the

o

upward path of the object begins at 0 ft. Replace v with +15 ft/sec.

o


Replace "a" with (-32.2 ft/(sec^2); this is the acceleration due to gravity.


Then we have the following, with the label F(t):


F(t) = 0 + (15 ft/sec)t + (1/2)(-32.2 ft)/(sec^2), or


F(t) = 15t - 16.1t^2. Thus, Choice D is correct.


Please note: To avoid confusion, please use " ^ " to denote exponentiation:


F(t) = -16t^2 + 15t

5 0
3 years ago
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