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padilas [110]
3 years ago
12

Please help me i need this ASAP

Mathematics
2 answers:
disa [49]3 years ago
8 0

Answer:

30 because of vertical angles.

tester [92]3 years ago
3 0

Answer:

It is 30

Step-by-step explanation:

Hope this helps have an amazing day/month/year!

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Which of these random samples represents a representative sample of the number of students in a middle school who walk to school
Westkost [7]

Answer:

c

Step-by-step explanation:

150 is a good sample of a middle school and students at lunch is random again because most students eat lunch

4 0
3 years ago
Find the mean, median, mode, and range of the data set.
kompoz [17]

Answer:

mean 11.14

Median 10

mode 10.

Explanation

Mean is sum of data divide by number of data.

Mode is the most appearing number.

3 0
3 years ago
How do you solve his with working
AlexFokin [52]
Check the picture below.

a)

so the perimeter will include "part" of the circumference of the green circle, and it will include "part" of the red encircled section, plus the endpoints where the pathway ends.

the endpoints, are just 2 meters long, as you can see 2+15+2 is 19, or the radius of the "outer radius".

let's find the circumference of the green circle, and then subtract the arc of that sector that's not part of the perimeter.

and then let's get the circumference of the red encircled section, and also subtract the arc of that sector, and then we add the endpoints and that's the perimeter.

\bf \begin{array}{cllll}
\textit{circumference of a circle}\\\\ 
2\pi r
\end{array}\qquad \qquad \qquad \qquad 
\begin{array}{cllll}
\textit{arc's length}\\\\
s=\cfrac{\theta r\pi }{180}
\end{array}\\\\
-------------------------------

\bf \stackrel{\stackrel{green~circle}{perimeter}}{2\pi(7.5) }~-~\stackrel{\stackrel{green~circle}{arc}}{\cfrac{(135)(7.5)\pi }{180}}~+
\stackrel{\stackrel{red~section}{perimeter}}{2\pi(9.5) }~-~\stackrel{\stackrel{red~section}{arc}}{\cfrac{(135)(9.5)\pi }{180}}+\stackrel{endpoints}{2+2}
\\\\\\
15\pi -\cfrac{45\pi }{8}+19\pi -\cfrac{57\pi }{8}+4\implies \cfrac{85\pi }{4}+4\quad \approx \quad 70.7588438888



b)

we do about the same here as well, we get the full area of the red encircled area, and then subtract the sector with 135°, and then subtract the sector of the green circle that is 360° - 135°, or 225°, the part that wasn't included in the previous subtraction.


\bf \begin{array}{cllll}
\textit{area of a circle}\\\\ 
\pi r^2
\end{array}\qquad \qquad \qquad \qquad 
\begin{array}{cllll}
\textit{area of a sector of a circle}\\\\
s=\cfrac{\theta r^2\pi }{360}
\end{array}\\\\
-------------------------------

\bf \stackrel{\stackrel{red~section}{area}}{\pi(9.5^2) }~-~\stackrel{\stackrel{red~section}{sector}}{\cfrac{(135)(9.5^2)\pi }{360}}-\stackrel{\stackrel{green~circle}{sector}}{\cfrac{(225)(7.5^2)\pi }{360}}
\\\\\\
90.25\pi -\cfrac{1083\pi }{32}-\cfrac{1125\pi }{32}\implies \cfrac{85\pi }{4}\quad \approx\quad 66.75884

7 0
3 years ago
Please help! I don't know what the reasons would be for statements 3 and 4
bezimeni [28]
3 = AIA ( Alternate Interior Angles)
4 = Definition of AIA
6 0
3 years ago
A card is drawn from a standard deck of 52 cards. What is the theoretical probability, as a decimal, of drawing a 9? Round the d
iragen [17]

There are 4 9's in a deck.

The probability would be 4 / 52 = 0.07692

Rounded to the nearest hundredth = 0.08

5 0
3 years ago
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