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Scilla [17]
3 years ago
6

player B's longest home run distance is 500 ft.There are 5280 ft in 1 mile. How many home runs would player B need to hit at his

longest distance for the total to be greater than 1 mile? explain
Mathematics
1 answer:
zhenek [66]3 years ago
6 0
11, 500 • 11 = 5,500
Hope this helps! Let me know if you need any further assistance!
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Considering that 30 out of 120 clients are willing to pay at least $95, we use the it's concept and find that there is a 0.25 = 25% probability that a customer is willing to pay at least $95.

<h3>What is a probability?</h3>

A probability is given by the <u>number of desired outcomes divided by the number of total outcomes</u>.

In this problem, we suppose that 30 out of 120 clients are willing to pay at least $95, hence:

p = \frac{30}{120} = 0.25

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More can be learned about the probability concept at brainly.com/question/15536019

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