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3 years ago

One number is seven more than six times another number. If the sum of the numbers is 21, find the numbers

Mathematics

2 answers:

dalvyx [7]3 years ago

4 0

Answer:

2 and 19 PLZ GIVE BRAINLIEST

Step-by-step explanation:

just did the question, 21= x + (7 + 6x)

21=7+7x

-7 -7

14=7x

14÷7=7x÷7

2=x

x=2

now 21-2=19

so answer is 2 and 19

Leviafan [203]3 years ago

3 0

Answer:the two numbers are 2 and 19

Step-by-step explanation:

Let one of the numbers be x

and the second be 7+ 6x

so that the sum of the two numbers which totals 21 be expressed as

x + (7+ 6x) = 21

x+ 7+6x= 21

7 + 7x = 21

7x= 14

x= 14/7 = 2

one of the numbers = 2

the other number given as

7+ 6x = 7+ 6 x 2= 7+12= 19

The numbers are 2 and 19 .

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3 years ago

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agasfer [191]

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Step-by-step explanation:

Given values:

$2xy =6.....(a)\\\\x-y= 3.....(b)\\\\$

After solve equation (a) we get

$\ equation: \\\\2xy= 6\\\\xy =\frac{6}{2} \\\\xy = 3.....(x)\\\\$

After solve equation (b) we get

$\ equation: \\\\x-y =3\\\\x= 3+y....(x1)\\$

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$y^2+3y-3=0\\\\\ compare \ the \ value \ with \ ay^2+by+c=0\\a= 1\\b=3\\c=-3\\\ Formula: \\y= \frac{-b\pm\sqrt{b^2-4ac}}{2a}\\y= \frac{-3\pm \sqrt{9+12}}{2}\\y= \frac{-3\pm \sqrt{21}}{2}\\$

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