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fredd [130]
3 years ago
9

Find the smallest number by which432 must be multiplied so that their products are a perfect sqaure​

Mathematics
1 answer:
snow_tiger [21]3 years ago
5 0

Answer:

i hope this help you

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HELP PLEASE !!!
Lana71 [14]
972-4=968 and 62-4=58
The highest common number between 968 and 58 is 2 so 968 in fractions is 484/2 and 58 is 29/2

If you multiply these two together you will get 14036/2
5 0
3 years ago
Harold has been hired as a salesman. He is paid a flat rate of $375 each week and earns an additional $14.25 commission for each
Andru [333]
The answer is
c. \: y = 14.25h + 375
5 0
3 years ago
If two angles in a triangle are 60° and 30°, is the third angle acute, obtuse, or right?​
Sindrei [870]

Answer: Right Angle

Step-by-step explanation:

And Since The Angles Of a Trangle Add Up To 180° When You Substract 90 From It You Remain With Another 90° Which Means The Angle Is Non Other Than a right angle traingle

60° + 30° = 90°

180° - 90° = 90°

∴ 90° = Right Angle Traingle

4 0
3 years ago
A boundary stripe 6 in. wide is painted around a rectangle whose dimensions are 120 ft by 230 ft. Use differentials to approxima
Nimfa-mama [501]

Answer:

350 square feet

Step-by-step explanation:

We are given that

Width of strip=6 in

Dimension of rectangle=20 ft\times 230 ft

We know that

Area  of rectangle ,A=xy

Differentiate

dA=\frac{\partial A}{\partial x}x+\frac{\partial A}{\partial y}y

We have \frac{\partial A}{\partial x}=y=230 ft

\frac{\partial A}{\partial y}=x=120

dx=\frac{12}{12}=1 ft

1 ft=12 in

Because 6 in added in both side of breadth

dy=\frac{12}{12}=1 ft

Because 6 in added on both sides of length of rectangle

Substitute the values

dA=230\times 1+120\times 1=350 ft^2

Hence, the number of square feet of paint in the strip=350 square feet

7 0
3 years ago
- A number r added to 3.7 is less than 1.2.
SIZIF [17.4K]

Answer:

3.7 + r < 1.2

Step-by-step explanation:

a number r added to 3.7 is 3.7 + r

New expression 3.7 + r should be less than 1.2 --->

3.7 + r < 1.2

7 0
3 years ago
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