Solve x2 + 12 = -11 by completing the square.which is the solution set of the equation

Solve the equation. \dfrac32 + b = \dfrac74 2 3 +b= 4 7 start fraction, 3, divided by, 2, end fraction, plus, b, equals, sta

Xelga [282]

Given:

The equation is

$\dfrac{3}{2}+b=\dfrac{7}{4}$

To find:

The value of b.

Solution:

We have,

$\dfrac{3}{2}+b=\dfrac{7}{4}$

Subtracting both sides by $\dfrac{3}{2}$ , we get

$b=\dfrac{7}{4}-\dfrac{3}{2}$

$b=\dfrac{7-2(3)}{4}$

$b=\dfrac{7-6}{4}$

$b=\dfrac{1}{4}$

Therefore, the value of b is $\dfrac{1}{4}$ .

3 0

3 years ago

Read 2 more answers

Half note times a whole note plus 2 quarter notes minus 3 half notes

Allisa [31]

B is your answer bc 2 times 4 is 8 plus 2 minus 6 is

5 0

3 years ago

Read 2 more answers

How to find the smallest integer k such that 60k is a perfect square

suter [353]

9514 1404 393

Answer:

k = 15

Step-by-step explanation:

Look for the missing factors that make all of the factors of 60k be squares.

60 = 2² × 3 × 5

The factors 3 and 5 each have an odd exponent (1), so those two factors must be part of k.

60k = 2² × 3 × 5 × k

is a perfect square when ...

3 × 5 = k = 15

For k = 15, 60k = 900 = 30²

6 0

3 years ago

The load that can be supported by a rectangular beam varies jointly as the width of the beam and the square of itsâ height, and

storchak [24]

The question is incomplete.Here is the complete question.

The load that can be supported by a rectangular beam varies jointly as the width of the beam and the square of its length, and inversely as the length of the beam. A beam 13 feet long, with a width of 6 inches and a height of 4 inches can support a maximum load of 800 pounds. If a similar board has a width of 8 inches and a height of 7 inches, how long must it be to support 1300 pounds?

Answer: It must be 392 inches or approximately 33 feet.

Step-by-step explanation: According to the question, the measures (width, length and height) of a beam and the weight it supports are in a relation of <u>proportionality</u>, i.e., if divided, the result is a constant.

For the first load:

width = 6in

height = 4in

length = 13ft or 156in

weight = 800lbs

Then, constant will be:

$\frac{6.4^{2}}{156} k = 800$

$k=\frac{800.156}{96}$

k = 1300

For the similar beam:

$\frac{8.7^{2}}{L}1300=1300$

L = 49.8

L = 392in or 32.8ft

A similar board will support 1300lbs if it has 392 inches or 32.8 feet long.

6 0

3 years ago

The temperature of a piece of metal was 32°C. It was then lowered into a glass of

Paul [167]

Answer:

12.5%

Step-by-step explanation:

Given that,

Initial temperature of a piece of metal = 32°C

Final temperature of the piece of metal = 36°С

We need to find the percentage increase in the temperature of the piece of metal. The percentage increase in any value is given by the relation as follows :

$\%=\dfrac{|\text{final value-initial value}|}{\text{initial value}}\times 100\\\\=\dfrac{36-32}{32}\times 100\\\\=12.5\%$

So, the required percentage increase in the temperature of the piece of metal is equal to 12.5%.

3 0

3 years ago