So I’m going to solve this using algebra OK?
So what you do is take the first integer as X.
Then we know that x(the first number) + X+2(the second number) is 288 right?
So we solve that saying x+x+2=288.
So 2X+2=288
2X+2-2=288-2 right?
So 2X=286.
So x is 286/2 right?
So x is 143.
Now the first number is 143 right?
So the second number should be 143+2 so 145.
I know they are not even but these are the solutions.
I don’t think there are any consecutive even numbers that add up to 288
Answer:
3 games
Step-by-step explanation:
The computation of the maximum number of games that he could buy is shown below:
= Amount available - already spent
= $75 - $28
= $47
If each game cost $15
So, the maximum no of games is
= $47 ÷ $15
= 3.133
= 3 games
Answer:
there are 20 different combinations if that was the question.
Step-by-step explanation:
Formula :
Combination(event 1) times Combinations (Event2)
Answer:
w=1.5 or w=13.5
Step-by-step explanation:
this is one answer:
multiply w on both sides to leave u with
4.5=3w
divide both sides by 3

1.5=w
_____________________
this is the second one if the first one is wrong:
multiply 4.5 on both sides so that the 4.5/w would leave u with just only w alone.
then 3*4.5=13.5
w=13.5
hope dis helps if not then im not dat smart enough ;?