a speedboat that costs $45,000 is depreciating at a rate of 20% per year. Find the value of the boat after 4 years.

Mathematics

1 answer:

son4ous [18]2 years ago

3 0

Answer:

$18,432

Step-by-step explanation:

After the first year, the speedboat is now worth $36,000 because 20% of 45,000 is 9,000, and 45,000 - 9,000 = 36,000. After the second year, it is now worth $28,800. After the third year, it is worth $23,040 since 20% of 28,800 is 5,760 and 28,800 - 5,760 = 23,040. After four years, the boat that once was worth $45,000 is now worth $18,432.

You might be interested in

A publisher needs to send many books to a local book retailer and will send the books in a combination of small and large boxes.

Paladinen [302]

Answer:

Answer:

\{ {{20x+30y=280} \atop {y=4x}} .{

y=4x

20x+30y=280

Where xx is the number of small boxes sent and yy is the number of large boxes sent.

Step-by-step explanation:

Let be xx the number of small boxes sent and yy the number of large boxes sent.

Since each small box can hold 20 books (20x20x ), each large box can hold 30 books (30y30y )and altogether can hold a total of 280 books, we can write the following equation to represent this:

20x+30y=28020x+30y=280

According to the information provided in the exercise, there were 4 times as many large boxes sent as small boxes. This can be represented with this equation:

y=4xy=4x

Therefore, the system of equation that be used to determine the number of small boxes sent and the number of large boxes sent, is:

\{ {{20x+30y=280} \atop {y=4x}} .{

y=4x

20x+30y=280

7 0

3 years ago

C <br> 5 in<br> 4 in<br> What is the length of the hypotenuse?

vlabodo [156]

Answer:

${c}^{2} = {5}^{2} + {4}^{2} \\ {c}^{2} = 25 + 16 \\ {c}^{2} = 41$