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34kurt
3 years ago
10

Mario vende dos autos a 30 000 dólares cada uno. En la venta de uno ganó el 20% y en la

Mathematics
1 answer:
Mariana [72]3 years ago
6 0

Answer:

Mario perdió dinero, perdió 2500 dólares

Step-by-step explanation:

En el primer caso, Mario está vendiendo su carro en 30 000 dólares. En otras palabras, el precio de venta es 30 000. Te dice que en el primer carro ganó 20%, o sea que su precio de venta es una incógnita que llamaremos x y gano 20% de x. Podemos expresarlo de esta manera

x = precio de compra carro 1

x + (20% de x) = 30 000

x = 100 % de x

(100% de x) + (20% de x) = 30 000

120% de x =30 000

120% = 1.2

1.2x = 30 000

x = 25 000

El segundo caso es bastante parecido. Te indica que el precio de venta sigue siendo el mismo, pero el precio de compra es diferente. El precio de venta sigue siendo 30 000, pero el precio de compra del segundo carro esta vez será "y". En este caso, pierde 20% del precio de compra, o osea, pierde 20% de y. Se puede expresar de la siguiente manera:

y = precio de compra carro 2

y - (20% de y) = 30 000

y = 100% de y

(100% de y) - (20% de y) = 30 000

80% de y = 30 000

80% = 0.8

0.8y = 30 000

y= 37 500

Entonces tenemos que el precio de compra del carro uno es 25 000 dólares y el precio de compra del carro dos es de 37 500. Si sumamos ambas cantidades, tenemos que ambos carros costaron 62 500 dólares. Como vendió esos dos autos a 30 000 dólares cada uno, recibió 60 000 dólares. El precio por el que vendió los autos (60 000) es menor al precio del que los compro (62 500), por lo que eso representa una perdida.

Para hallar la cantidad que ganó o perdió (en este caso perdió) debes restar el precio de venta menos el precio de compra.

60 000 - 62 500 = -2 500

Como es un número negativo, representa una perdida.

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