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3 years ago

How does a water well affect ground water?

Physics

1 answer:

Evgen [1.6K]3 years ago

6 0

Answer:

Pumping a well lowers the water level around the well to form a cone of depression in the water table. If the cone of depression extends to other nearby wells, the water level in those wells will be lowered. The cone develops in both shallow water-table and deeper confined-aquifer systems.

Explanation:

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Your 5th-grade brother keeps telling you that speed and velocity are the same

ivanzaharov [21]

Answer:

Speed is the time rate at which an object is moving along a path, while velocity is the rate and direction of an object's movement.

<u>please mark as brainly</u>

7 0

3 years ago

Two people push a box, both in the same

anyanavicka [17]

Answer:

300N

Explanation:

If both people push the box in the same direction the force applied to the box is the sum of the N from both peoplef:

100N + 200N = 300N

4 0

3 years ago

A car drives around a racetrack for 30 seconds. what do you need to know to calculate the average velocity of the car?

boyakko [2]

The time is given, and you want to find the average velocity. To do this, you need to know the distance covered by the driver around the racetrack in that 30 seconds. You divide this by the time, then you will obtain the average velocity in units of, say meters per second.

8 0

3 years ago

Read 2 more answers

Which equation relates charge, time, and current?

san4es73 [151]

Answer:

The first one

Explanation:

8 0

3 years ago

A cricket ball has mass 0.155 kg. If the velocity of a bowled ball has a magnitude of 35.0 m/s and the batted ball's velocity is

FinnZ [79.3K]

Answer:

Magnitude of change in momentum = 4.65 kg.m/s

Magnitude of impulse = 4.65 kg.m/s

Magnitude of the average force applied by the bat = 1550 N

Explanation:

Mass of the cricket ball, m = 0.155 kg

Initial velocity of the ball, u = 35.0 m/s

final velocity of the ball after hitting the bat, v = 65.0 m/s

Time of contact, t = 2.00 ms = 2.00 × 10⁻³ s

Now,

Magnitude of change in momentum = Final momentum - Initial momentum

Magnitude of change in momentum = ( m × v ) - ( m × u )

Magnitude of change in momentum = ( 0.155 × 65 ) - ( 0.155 × 35 )

Magnitude of change in momentum = 10.075 - 5.425 = 4.65 kg.m/s

Now, Magnitude of impulse = change in momentum

thus,

Magnitude of impulse = 4.65 kg.m/s

Now,

magnitude of the average force applied by the bat = $\frac{\textup{Impulse}}{\textup{Time}}$

magnitude of the average force applied by the bat = $\frac{\textup{4.65}}{\textup{3}\times\textup{10}^{-3}}$

Magnitude of the average force applied by the bat = 1550 N

6 0

4 years ago