Answer:
Explanation:
Potential energy on the surface of the earth 
= - GMm/ R
Potential at height h 
=  - GMm/ (R+h)
Potential difference
= GMm/ R -  GMm/ (R+h)
= GMm ( 1/R - 1/ R+h )
= GMmh / R (R +h)
This will be the energy needed  to launch an object from the surface of Earth to a height h above the surface.
Extra  energy is needed to get the same object into orbit at height h
= Kinetic energy of the orbiting object at height h 
= 1/2 x potential energy at height h 
= 1/2 x GMm / ( R + h)
 
        
             
        
        
        
The distance an object falls from rest through gravity is
                         D  =  (1/2) (g) (t²)
            Distance  =  (1/2 acceleration of gravity) x (square of the falling time)
We want to see how the time will be affected 
if  ' D ' doesn't change but ' g ' does. 
So I'm going to start by rearranging the equation
to solve for ' t '.
                                                      D  =  (1/2) (g) (t²)
Multiply each side by  2 :         2 D  =            g    t²  
Divide each side by ' g ' :      2 D/g =                  t² 
Square root each side:        t = √ (2D/g)
Looking at the equation now, we can see what happens 
to ' t ' when only ' g ' changes:  
-- ' g ' is in the denominator; so bigger 'g' ==> shorter 't'
                                             and smaller 'g' ==> longer 't' .
-- They don't change by the same factor, because  1/g  is inside
the square root.  So 't' changes the same amount as  √1/g  does.
Gravity on the surface of the moon is roughly  1/6  the value
of gravity on the surface of the Earth.
So we expect ' t ' to increase by  √6  =  2.45 times.
It would take the same bottle  (2.45 x 4.95) = 12.12 seconds
to roll off the same window sill and fall 120 meters down to the
surface of the Moon.
        
                    
             
        
        
        
        
Answer:
write the equation of motion go over the centre of mass
Explanation:
 the center of mass of a distribution of mass in space (sometimes referred to as the balance point) is the unique point where the weighted relative position of the distributed mass sums to zero. This is the point to which a force may be applied to cause a linear acceleration without an angular acceleration.
 
        
             
        
        
        
Answer:
1 astronomical unit is the average distance from the Earth to the Sun; approximately 150 million km. At its closest point, Saturn is 9 AU, and then at its most distant point, it's 10.1 AU. Saturn's average distance from the Sun is 9.6 AU. We have written many articles about Saturn for Universe Today.
Explanation: