Answer:
a = 4
Step-by-step explanation:
Here, we want to write and solve the given equation
a - 2.5 = 1.5
a = 2.5 + 1.5
a = 4
To check, we simply substitute a = 4
That would be;
4-2.5 = 1.5
This is correct
Answer:
2 5/12
Step-by-step explanation:
8 5/6 + 2 3/4 = 8 10/12 + 2 9/12 = 10 19/12 = 10 + 1 7/12 = 11 7/12
13 12/12 - 11 7/12 = 2 5/12
Let "a" and "s" represent the costs of advance and same-day tickets, respectively. Your problem statement gives you two relations.
.. a + s = 35 . . . . . the combined cost of one of each is 35
.. 15a +40s = 900 . . total paid for this combination of tickets was 900
There are many ways to solve these equations. You've probably been introduced to "substitution" and "elimination" (or "addition"). Using substitution for "a", we have
.. a = 35 -s
.. 15(35 -s) +40s = 900 . . substitute for "a"
.. 25s +525 = 900 . . . . . . . simplify
.. 25s = 375 . . . . . . . . . . . .subtract 525
.. s = 15 . . . . . . . . . . . . . . .divide by 25
Then
.. a = 35 -15 = 20
The price of an advance ticket was 20.
The price of a same-day ticket was 15.
Answer:
Step-by-step explanation:
Salvage value=$1000
Purchased value=$11,000
In order to find the balance in accumulated depreciation at december 31,2015 using the units of activity we will use the following formula:
In the above equation $10000 came from Purchased value - salvage Value
