Determine whether each of the functions log(n + 1) and log(n2 + 1) is o(log n)

1 answer:

8 0

Assuming the order required is as n-> inf.

As n->inf, o(log(n+1)) -> o(log(n)) since the 1 is insignificant compared with n.

We can similarly drop the "1" as n-> inf, the expression becomes log(n^2+1) ->
log(n^2)=2log(n) which is still o(log(n)).

So yes, both are o(log(n)).

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5. -2 = p - 1<br> Help me pleaseee

dangina [55]

Assuming you are trying to find the value of p:

You would add 1 to each side to make the p alone

-2 =p - 1
+1 +1

-1 = p

To check, you can put p in the original equation

-2 = -1 - 1

-2 = -2 which means this is correct

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3 years ago

Identify the horizontal asymptote of f(x) =x2+5x-3/4x-1

Pachacha [2.7K]

since the numerator is x² + 5x - 3, and therefore has a degree of 2, whilst the denominator, 4x¹ - 1, has a degree of 1, therefore, there's no horizontal asymptote.

recall, we only get a horizontal asymptote if the denominator's expression degree is equals or greater than that of the numerator's.

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lesantik [10]

Answer:

a) 0.778

b) 0.9222

c) 0.6826

d) 0.3174

e) 2 drivers

Step-by-step explanation: