If there were 35 cows and the ratio for cows to horses is 7:4, then there would be 20 horses because 35 divided by 5 is 7 and 20 divided by 5 is 4.
No two <em>intergers</em> can solve this problem. If you're not in Algebra II yet, the answer is probably "none."
Just look at the factor pairs of 25:
1 × 25
-1 × 25
5 × 5
-5 × -5
Clearly none of those can add up to 6.
If you want the more complex answer, I'll show you how here. If you don't understand why it doesn't work, that's okay. I just want you to see that there's not an actual answer to the problem.
a+b = 6
a = 6-b
ab = 25
(6-b)b = 25
6b -b² = 25
-b² + 6b = 25
b² -6b = -25
Factor by splitting the middle.
Half of -6 is -3, (-3)² = 9. Add this to each side.
b² -6b + 9 = -16
Factor the perfect square trinomial.
(b-3)² = -16
Take the square root of each side.
b-3 = 4i
b = 3+4i
a+b = 6
a+3+4i = 6
a= 3-4i
<em>(The "i" stands for an imaginary number, specifically, the square root of -1.)</em>
Answer:
Domain: -4 < x < 4
Zeros: (-2, 0), (0, 0) and (2, 0)
The function is positive if: 0 < x < 2
The function is negative if: -4 < x < 0 and 2 < x < 4
Step-by-step explanation:
Domain of the function are those x values where the function is defined, For this case, -4 < x < 4
Zeros of a function are those x values where y = 0, that is, the graph intersect x-axis. For this case, the points are: (-2, 0), (0, 0) and (2, 0)
The function is positive if the graph o the function is above x-axis. For this case, the function is positive at the interval (0, 2)
The function is negative if the graph o the function is below x-axis. For this case, the function is negative at the intervals (-4, 0) and (2, 4)
Answer:
y=-4x-5
Step-by-step explanation:
The answer is parther. Be
