All categories

3 years ago

I need help on 8,9,and 10 please good luck

Mathematics

2 answers:

mina [271]3 years ago

4 0

Number 8 is 15 I think

pishuonlain [190]3 years ago

3 0

The answer for 8 is 15

You might be interested in

A 10 pound bag of grapes costs $14.00. How many pounds of grapes can you get for $7.00?

GarryVolchara [31]

5pounds cfdthjhgddvnirdvjitdxvj

6 0

3 years ago

(2a^x + b^x)^2 i need help ASAP

Finger [1]

Answer:

4 $a^{2x}$ + 4 $a^{x}$ $b^{x}$ + $b^{2x}$

Step-by-step explanation:

Using the rule of exponents

$a^{m}$ × $a^{n}$ ⇔ $a^{(m+n)}$

Given

(2 $a^{x}$ + $b^{x}$ ) = (2 $a^{x}$ + $b^{x}$ )(2 $a^{x}$ + $b^{x}$ )

Each term in the second factor is multiplied by each term in the first factor, that is

2 $a^{x}$ (2 $a^{x}$ + $b^{x}$ ) + $b^{x}$ (2 $a^{x}$ + $b^{x}$ ) ← distribute both parenthesis

= 4 $a^{2x}$ +2 $a^{x}$ $b^{x}$ + 2 $a^{x}$ $b^{x}$ + $b^{2x}$ ← collect like terms

= 4 $a^{2x}$ + 4 $a^{x}$ $b^{x}$ + $b^{2x}$

6 0

3 years ago

Shawn has 25 coins, all nickels and dimes. The total value is $2.00. How many of each coin does he have ?

Sergeu [11.5K]

Answer:

$\boxed{15 \ dime \ and \ 10 \ nickel \ coins}$

Step-by-step explanation:

1 dime = 10 cents

1 nickel = 5 cents

So,

If there are 15 dimes

=> 15 dimes = 15*10 cents

=> 15 dimes = 150 cents

=> 15 dimes = $1.5

Rest is $0.5

So, for $0.5 we have 10 nickels coins

=> 10 nickels = 10*5

=> 10 nickels = 50 cents

=> 10 nickel coins = $0.5

Together it makes $2.00

5 0

4 years ago

Se tienen 240 cajas con 25 bolsas cada una . Si cada bolsa pesa 0.69 kg. Cual es el peso del cafe?

hammer [34]

Answer:

Step-by-step explanation:

There are 240 boxes with 25 bags each. If each bag weighs 0.69 kg. What is the weight of coffee?

4 0

3 years ago

This week, we are covering relationships that can be approximated by linear equations. For instance, y = 453x + 3768 represents

lana [24]

Answer:

See explanation below.

Step-by-step explanation:

We assume that the data is given by :

x: 30, 30, 30, 50, 50, 50, 70,70, 70,90,90,90

y: 38, 43, 29, 32, 26, 33, 19, 27, 23, 14, 19, 21.

Where X represent the cost for scholarships in thousands of dollars and y represent the cost of life for an academic semester (The data comes from the web)

We can find the least-squares line appropriate for this data.

For this case we need to calculate the slope with the following formula:

$m=\frac{S_{xy}}{S_{xx}}$

Where:

$S_{xy}=\sum_{i=1}^n x_i y_i -\frac{(\sum_{i=1}^n x_i)(\sum_{i=1}^n y_i)}{n}$

$S_{xx}=\sum_{i=1}^n x^2_i -\frac{(\sum_{i=1}^n x_i)^2}{n}$

So we can find the sums like this:

$\sum_{i=1}^n x_i = 30+30+30+50+50+50+70+70+70+90+90+90=720$

$\sum_{i=1}^n y_i =38+43+29+32+26+33+19+27+23+14+19+21=324$

$\sum_{i=1}^n x^2_i =30^2+30^2+30^2+50^2+50^2+50^2+70^2+70^2+70^2+90^2+90^2+90^2=49200$

$\sum_{i=1}^n y^2_i =38^2+43^2+29^2+32^2+26^2+33^2+19^2+27^2+23^2+14^2+19^2+21^2=9540$

$\sum_{i=1}^n x_i y_i =30*38+30*43+30*29+50*32+50*26+50*33+70*19+70*27+70*23+90*14+90*19+90*21=17540$

With these we can find the sums:

$S_{xx}=\sum_{i=1}^n x^2_i -\frac{(\sum_{i=1}^n x_i)^2}{n}=49200-\frac{720^2}{12}=6000$

$S_{xy}=\sum_{i=1}^n x_i y_i -\frac{(\sum_{i=1}^n x_i)(\sum_{i=1}^n y_i)}=17540-\frac{720*324}{12}{12}=-1900$

And the slope would be:

$m=-\frac{1900}{6000}=-0.317$

Nowe we can find the means for x and y like this:

$\bar x= \frac{\sum x_i}{n}=\frac{720}{12}=60$

$\bar y= \frac{\sum y_i}{n}=\frac{324}{12}=27$

And we can find the intercept using this:

$b=\bar y -m \bar x=27-(-0.317*60)=46.02$

So the line would be given by:

$y=-0.317 x +46.02$

We have an inverse linear relationship since the slope is negative between the variables of interest.

8 0

4 years ago