Total exterior angle for all polygons = 360°
= 360°/17.14°
= 21.003°
= 21 exterior angles
thus, the polygon have 21 sides.
Inequality Form: x>3
Interval Notation: (3, infinity)
The answer is 221. And it’s solved with PEMDAS
Full Question:
The 4th term of a g.p. is 40 and the 10th term in the sequence is 2560, what is the 11th term in the sequence ?
Answer:
the 11 the term is 5120
Step-by-step explanation:
Given
Geometry Progression
4th term = 40
10th term = 2560
Required
11 term.
The nth term of a geometric sequence is calculated as follows
Tₙ = arⁿ⁻¹
For the 4th term, n = 4 and Tₙ = 40
Substitute these in the given formula; this gives
40 = ar⁴⁻¹
40 = ar³. --;; equation 1
For the 10th term, n = 10 and Tₙ = 2560
Substitute these in the given formula; this gives
2560 = ar¹⁰⁻¹
2560 = ar⁹. --;; equation 2
Divide equation 2 by 1. This gives
2560/40 = ar⁹/ar³
64 = r⁹/r³
From laws of indices
64 = r⁹⁻³
64 = r⁶
Find 6th root of both sides
(64)^1/6 = r
r = (2⁶)^1/6
r = 2
Substitute r = 2 in equation 1
40 = ar³. Becomes
40 = a * 2³
40 = a * 8
40 = 8a
Divide both sides by 8
40/8 = 8a/8
5 = a
a = 5.
Now, the 11 term can be solved using Tₙ = arⁿ⁻¹ where n = 11
So,
Tₙ = arⁿ⁻¹ becomes
Tₙ = 5 * 2¹¹⁻¹
Tₙ = 5 * 2¹¹⁻¹
Tₙ = 5 * 2¹⁰
Tₙ = 5 * 1024
Tₙ = 5120.
Henxe, the 11 the term is 5120
Answer:
(a) Slope and y-intercept; (b) y = mx; (c) y = x + b
Step-by-step explanation:
1. Need to know
Slope and y-intercept.
You use these numbers to calculate one other point. Then you draw a straight line between the y-intercept and the other point to get the graph.
2. y-Intercept = 0
The form of the equation is y = mx + b, where b is the y-intercept.
If the intercept is zero, b = 0, and the equation has the form
y = mx
The graph is a straight line passing through the origin.
3. Slope = 1
m represents the slope. If m = 1, the equation has the form
y = x + b
If the axes are scaled equally, the graph is a straight line that crosses the y-intercept at an angle of 45°.
