I'm assuming hardware.
Remember, Hard = Physical.
If that's not it, try peripherals.
Complete Question:
Recall that with the CSMA/CD protocol, the adapter waits K. 512 bit times after a collision, where K is drawn randomly. a. For first collision, if K=100, how long does the adapter wait until sensing the channel again for a 1 Mbps broadcast channel? For a 10 Mbps broadcast channel?
Answer:
a) 51.2 msec. b) 5.12 msec
Explanation:
If K=100, the time that the adapter must wait until sensing a channel after detecting a first collision, is given by the following expression:
The bit time, is just the inverse of the channel bandwidh, expressed in bits per second, so for the two instances posed by the question, we have:
a) BW = 1 Mbps = 10⁶ bps
⇒ Tw = 100*512*(1/10⁶) bps = 51.2*10⁻³ sec. = 51.2 msec
b) BW = 10 Mbps = 10⁷ bps
⇒ Tw = 100*512*(1/10⁷) bps = 5.12*10⁻³ sec. = 5.12 msec
Answer:
Option A is the correct choice answer for the above question.
Explanation:
In an MS-Powerpoint document, when a user wants to copy the selected shape and drag that shape for use in slides then he needs to--
- Select the shape
- Press the Ctrl key and
- drag that shape on the slide of the powerpoint.
Then the user gets the shape on the slide for their personal use.
The question scenario also suggests the same which is described above. hence Option A is the correct answer while the other is not because--
- Option B suggests 'ESC' which is used to escape any running program.
- Option C suggests about ALT key which is of no use for the MS-Powerpoint document.
- Option D suggests about TAB key which is used to make the space between two texts or diagram.
