The greatest perimiter
let's experiment weather we want to have sides with as close to each other as possible, or with as far apart form each other
so if we have lenth times width, peimiter=legnth+legnth+widht+width
1 times 39:perimiter=80
3 times 13:perimiter=52
so we want one side as small as possible
0.1 times 360:perimiter=720.2
let's see how far we can go
0.00000000000000000001 times 3600000000000000000000=3,600,000,000,000,000,000,000.00000000000000000001
you get the idea
that is a really big perimiter
if you can be that exact
so just make a really small decimal
if you haven't learned decimals yet and only know whole numbers then
80 ft is the greatest perimiter made (with sides of 39,1,39,1)
11.
so we do 40 / 3.667 (3 and 2/3, as far as i can tell) to get x.
so it's 10.9, or 11.
To answer this, you need to know the general form of an absolute value function. the equation for this is f(x<span>) = </span>a|x<span> - </span>h<span>| + </span>k, and in this equation, the vertex is (h, k).
with that information, you can see that your vertex will be (-5, 7). you must take the negative for 5 because the general equation states that your h value is usually subtracted from x. to check your vertex, try plugging it into your general equation:
f(x) = a|x - (-5)| + 7
f(x) = a|x + 5| + 7 ... you see that this matches your given equation. this last part here was just to show why your 5 must be negative; your answer is bolded.
Step-by-step explanation:
ans is 23 please mark me as brainlist please
