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Maurinko [17]
3 years ago
14

Cant figure this out help please

Mathematics
2 answers:
Eva8 [605]3 years ago
8 0

Answer:

5. is 75 and 6. is 60

Step-by-step explanation:

5. 150/2 which is the first coordinate is 75

6. 180/3 is 60

777dan777 [17]3 years ago
7 0
5 is 75 and 6 is 60!!
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Help please PLEASE IM FREAKING SERIOUS IF I DONT FINISH IT BY 9 IM DEAD ILL GIVE 50 POINTS HELP PLEASE IM ACTUA;LY FRICKIN SERRI
yuradex [85]

Answer:

1/4 i think

Step-by-step explanation:

hope this helps

if i was right pls mark brainliest

6 0
2 years ago
Which value for x makes the sentence true?
Minchanka [31]

Answer:

☆*: .。..。.:*☆☆*: .。..。.:*☆☆*: .。..。.:*☆☆

Hi! The answer to your question is 31

Step-by-step explanation:

☆*: .。..。.:*☆☆*: .。..。.:*☆☆*: .。..。.:*☆☆

☆Brainliest is greatly appreciated!☆

Hope this helps!!

- Brooklynn Deka

4 0
3 years ago
For the following cylinder, what is the area of the two bases in square centimeters?
Bezzdna [24]
Cylinder formula is 2pi(r)^2 + 2pi(r)h

2pi(0.25)^2 + 2pi(0.25)(1)

Chuck that in calculator and evaluate
8 0
3 years ago
Explain how to write a quadratic equation given the following three points on the graph (5,31) (3,11) (0,11)
masha68 [24]

Given:

The graph of a quadratic function passes through the points (5,31) (3,11) (0,11).

To find:

The equation of the quadratic function.

Solution:

A quadratic function is defined as:

y=ax^2+bx+c            ...(i)

It is passes through the point (0,11). So, substitute x=0,y=11 in (i).

11=a(0)^2+b(0)+c

11=c

Putting c=11 in (i), we get

y=ax^2+bx+11               ...(ii)

The quadratic function passes through the point (5,31). So, substitute x=5,y=31 in (ii).

31=a(5)^2+b(5)+11

31-11=a(25)+5b

20=25a+5b

Divide both sides by 5.

4=5a+b                  ...(iii)

The quadratic function passes through the point (3,11). So, substitute x=3,y=11 in (ii).

11=a(3)^2+b(3)+11

11-11=a(9)+3b

0=9a+3b

Divide both sides by 3.

0=3a+b                 ...(iv)

Subtracting (iv) from (iii), we get

4-0=5a+b-3a-b

4=2a

\dfrac{4}{2}=a

2=a

Putting a=2 in (iv), we get

0=3(2)+b

0=6+b

-6=b

Putting a=2,b=-6 in (ii), we get

y=(2)x^2+(-6)x+11

y=2x^2-6x+11

Therefore, the required quadratic equation is y=2x^2-6x+11.

7 0
3 years ago
14. Ginny has 26 tests to correct. It takes her
katovenus [111]

Answer:

13 hours

Step-by-step explanation:

If she has 26 tests and it takes her Half an hour to correct each test, we know here's are two half an hour a in one hour so we can then divide 26 by 2 to get 13.

7 0
3 years ago
Read 2 more answers
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