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Ber [7]
2 years ago
9

un tren salió de la estación a las 9:45:27. Si dos horas y media más tarde ha llegado a su destino, ¿a qué hora llegó?

Mathematics
2 answers:
irina1246 [14]2 years ago
7 0

Answer:

12.15.27

Step-by-step explanation:

¡Espero que esto ayude mucho!

Trava [24]2 years ago
3 0

Answer:

12.15.27

Porq es así

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False this statement is false
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17/13 = y/10 solve for y and round to the nearest tenth
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\frac{17}{13}  =  \frac{y}{10}

17 \times 10 = y \times 13

170 = 13y

y =  \frac{170}{3}  = 56.6666....

56.6666... to the nearest tenth is <u>57</u>.

4 0
3 years ago
What is the answer to 4 (2/5) /6
coldgirl [10]

Answer:

= 4/15

Step-by-step explanation:

=4 . 2/5  /6

= 4/15

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Plssss help<br><br>use multiplication to solve the proportion​
kobusy [5.1K]

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Its 7.333333333333333333  (3 forever)

First you isolate y onto one side of the equation

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7 0
3 years ago
The Great Pyramid in Giza, Egypt, is a square pyramid. The dimensions of the pyramid at the time of its completion are shown in
ryzh [129]

Answer:

Area of square pyramid is 153883.8\ m^{2}.

Step-by-step explanation:

Diagram of the given scenario is shown below,

Given that,

The Great Pyramid in Giza, Egypt is a square pyramid. The area of base shape is made up with square is 154 \ m^{2}. The side of the square is 230 \ m and The height of each triangle is 187 \ m.

So,    Area of Square shape  = 154 \ m^{2}

         Side of square = 230 \ m

      Height of each triangle = 187 \ m

Finding the Height of triangular shape which is here known as slant height.

 In Δ ABO, applying Right angle pythagorean Theorem,

                  Base (BO) =  \frac{230}{2} = 115\ m

                Height (AO) = 187\ m

Now,      

∴                   AB^{2} = AO^{2} \ + \ BO^{2}

⇒                    AB= \sqrt{AO^{2} \ + \ BO^{2}  }

⇒                   AB= \sqrt{187^{2} \ + \ 115^{2}  }

⇒                   AB= \sqrt{34969 \ + \ 13225   }

⇒                   AB= 219.53 \ m

Then,

           Area of square pyramid = area \ of \ square + \ 4\times area \ of \ traiangle

                                                   = side\times side + 4\times\frac{1}{2}\times AB\times Base  

                                                   = 230\times 230 \  + 2\times 219.53\times 230

                                                   = 52900 + 100983.8

                                                   = 153883.8 \ m^{2}

Hence, Area of square pyramid is 153883.8\ m^{2}.

                   

6 0
3 years ago
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