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guajiro [1.7K]
3 years ago
9

Kasi bought 7 pounds of mozzarella cheese. Each pound costs $4.29. About how much did he spend all together?

Mathematics
2 answers:
svp [43]3 years ago
7 0
$30.03 because it is 4.29 seven times
Fiesta28 [93]3 years ago
5 0
The answer is $30.03 because she got 7 pounds of cheese for $4.29 each.
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C2 = 39<br><br> (c squared) <br><br> please help :(
iVinArrow [24]

<em>Answer:</em>

<em></em>\boxed{c = \sqrt{39} / c= - \sqrt{39} }<em></em>

<em>This " / " means or, btw!</em>

<em>Step-by-step explanation:</em>

<em></em>c^2 = 39<em></em>

<em>⇒Take square root.</em>

<em></em>c =<em> ± </em>\sqrt{39}<em></em>

<em></em>c = \sqrt{39}<em> or </em>c = -\sqrt{39}<em></em>

<em>Hope this helped you!</em>

7 0
2 years ago
An SRS of 350 high school seniors gained an average of x¯=21 points in their second attempt at the SAT Mathematics exam. Assume
Lynna [10]

Answer:

a) 21-2.58\frac{52}{\sqrt{350}}=13.83  

21+2.58\frac{52}{\sqrt{350}}=28.17  

So on this case the 99% confidence interval would be given by (13.83;28.17)  

b) ME=2.58\frac{52}{\sqrt{350}}=7.17

c) ME=2.58\frac{52}{\sqrt{100}}=13.42

d) D. Decreasing the sample size increases the margin of error, provided the confidence level and population standard deviation remain the same.

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

Part a

\bar X=21 represent the sample mean  

\mu population mean (variable of interest)  

\sigma=52 represent the population standard deviation  

n=350 represent the sample size  

99% confidence interval  

The confidence interval for the mean is given by the following formula:  

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}} (1)  

Since the Confidence is 0.99 or 99%, the value of \alpha=0.01 and \alpha/2 =0.005, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.005,0,1)".And we see that z_{\alpha/2}=2.58  

Now we have everything in order to replace into formula (1):  

21-2.58\frac{52}{\sqrt{350}}=13.83  

21+2.58\frac{52}{\sqrt{350}}=28.17  

So on this case the 99% confidence interval would be given by (13.83;28.17)  

Part b

The margin of error is given by:

ME=2.58\frac{52}{\sqrt{350}}=7.17

Part c

The margin of error is given by:

ME=2.58\frac{52}{\sqrt{100}}=13.42

Part d

As we can see when we reduce the sample size we increase the margin of error so the best option for this case is:

D. Decreasing the sample size increases the margin of error, provided the confidence level and population standard deviation remain the same.

6 0
2 years ago
Pls help answer this soon!!!!!
vladimir1956 [14]
13a) y = 0.45x

13b) 52 * 0.45 = 23.4

13c) I will let u figure this one out
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20 is 40% of what number
pantera1 [17]

it depends what the number is

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Tpy6a [65]

Answer:

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Step-by-step explanation:

i really don't know i'm doing overdue work to

5 0
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