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cupoosta [38]
3 years ago
11

HELPPPPPPPPPPPPPPPPPPPP PLSSSS

Mathematics
1 answer:
Effectus [21]3 years ago
7 0
15.5 is the awnser as 3.1*5 is 15.5 you would just times 5 by your night # witch is 3.1
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Find the midpoint M of the line segment joining the points C = (-1, -1) and D = (5, -5). ​
Nadusha1986 [10]

Answer:

The midpoint between the joining points C and D is (2, -3)

Step-by-step explanation:

How to find a midpoint

  • 1: Label the coordinates(x₁,y₁) and (x₂,y₂).
  • 2: Input the values into the formula.
  • 3: Add the values in the parentheses and divide each result by 2.
  • 4: The new values form the new coordinates of the midpoint.

Suppose we have a line segment and want to cut that section into two equal parts. To do so, we need to know the center. We can achieve this by finding the midpoint. You could measure with a ruler or just use a formula involving the coordinates of each endpoint of the segment. The midpoint is simply the average of each coordinate of the section, forming a new coordinate point. We shall illustrate this below.

Midpoint formula

If we have coordinates (x₁,y₁) and (x₂,y₂), then the midpoint of these coordinates is determined by (x₁ + x₂)/2, (y₁ + y₂)/2. This forms a new coordinate you can call (x₃,y₃).  It is possible to divide a line segment into any given ratio, not just 1:1.

7 0
1 year ago
3(x-2)*2-3? What's the y intercept x intercept vertex and the axis of symmetry ( *2 means the 2 power)
Rama09 [41]
(3x - 2)×2 - 3
6x - 4 -3
6x - 7
8 0
3 years ago
Convert standard to slope-intercept forms. 1. Standard form: 10x − 7y = −8
garri49 [273]

Answer:

Step-by-step explanation:

-7y = -10x - 8

y = 10/7x + 8/7

8 0
3 years ago
If you draw four cards at random from a standard deck of 52 cards, what is the probability that all 4 cards have distinct charac
mezya [45]

There are \binom{52}4 ways of drawing a 4-card hand, where

\dbinom nk = \dfrac{n!}{k!(n-k)!}

is the so-called binomial coefficient.

There are 13 different card values, of which we want the hand to represent 4 values, so there are \binom{13}4 ways of meeting this requirement.

For each card value, there are 4 choices of suit, of which we only pick 1, so there are \binom41 ways of picking a card of any given value. We draw 4 cards from the deck, so there are \binom41^4 possible hands in which each card has a different value.

Then there are \binom{13}4 \binom41^4 total hands in which all 4 cards have distinct values, and the probability of drawing such a hand is

\dfrac{\dbinom{13}4 \dbinom41^4}{\dbinom{52}4} = \boxed{\dfrac{2816}{4165}} \approx 0.6761

4 0
2 years ago
(PLEASE HELP!!)
umka2103 [35]
Congruent because 2 is a larger number then one and 1 is a smalled number then 2
7 0
2 years ago
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