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zhuklara [117]
3 years ago
11

Find the area of the polygon.

Mathematics
1 answer:
jolli1 [7]3 years ago
3 0

Answer:

7. 15.5

8. 12

Step-by-step explanation:

Question 7 equation: \frac{3*1}{2} + \frac{5+2}{2} * 4=1.5 + 3.5 * 4 = 1.5 + 14 = 15.5.

Question 8 equation: (\frac{2*2}{2} * 2) + (\frac{4*2}{2} *2) = 4 + 8 = 12.

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Explain how to evaluate simplify and convert to radical form (x^3/8)^3/4
Vaselesa [24]

Answer:

(x^\frac{3}{8})^\frac{3}{4}  = \sqrt[32]{x^9}

Step-by-step explanation:

Given

(x^\frac{3}{8})^\frac{3}{4}

Required

Convert to radical form

(x^\frac{3}{8})^\frac{3}{4}

Evaluate the exponents

(x^\frac{3}{8})^\frac{3}{4} = x^\frac{3*3}{8*4}

(x^\frac{3}{8})^\frac{3}{4} = x^\frac{9}{32}

Split the exponent

(x^\frac{3}{8})^\frac{3}{4} = (x^9)^\frac{1}{32}

Apply the following law of indices

(x^a)^\frac{1}{b} = \sqrt[b]{x^a}

So, we have:

(x^\frac{3}{8})^\frac{3}{4}  = \sqrt[32]{x^9}

3 0
3 years ago
Please help me out guys. The photo will show you what to do. 50 points cause I need it done fast
Nonamiya [84]

Answer:

a) starting height: 5.5 ft

b) hang time: 5.562 seconds

c) maximum height: 126.5 ft

d) time to maximum height: 2.75 seconds

Step-by-step explanation:

a) The starting height is the height at t=0.

h(0) = -16·0 +88·0 +5.5

h(0) = 5.5

The starting height is 5.5 feet.

__

b) The ball is in the air between t=0 and the non-zero time when h(t) = 0. We can find the latter by solving ...

-16t^2 + 8t +5.5 = 0

t^2 -(11/2)t = 5.5/16 . . . . . subtract 5.5, then divide by -16

t^2 -(11/2)t +(11/4)^2 = (5.5/16) +(11/4)^2 . . . . complete the square

(t -11/4)^2 = 126.5/16 . . . . . . . . . . . . . . . . . . . . call this [eq1] for later use

t -11/4 = √7.90625

t = 2.75 +√7.90625 ≈ 5.562

The ball will be in the air about 5.562 seconds.

__

c) If we multiply [eq1] above by -16 and add the constant on the right, we get the vertex form of the height equation:

h(t) = -16(t -11/4) +126.5

The vertex at (2.75, 126.5) tells us ...

The maximum height of the ball is 126.5 feet.

__

d) That same vertex point tells us ...

The maximum height will be reached at t = 2.75 seconds.

_____

If you really need answers fast, a graphing calculator can give them to you in very short order (less than a minute).

6 0
3 years ago
look at the figure shown below which step should be used to prove that point a is equidistant from points c and b
JulijaS [17]
D
is certainly wrong. You could extend the length of AD as far as you want and the two triangles (ABD and ACD) would still be congruent.

C
is wrong as well. The triangles might be similar, but they are more. They are congruent.

B
You don't have to prove that. It is given on the way the diagram is marked.

A
A is your answer. The two triangles are congruent by SAS 
3 0
3 years ago
Which one doesn’t belong with the other three? Explain your reasoning plz plz answer #3
Ahat [919]

The box provides some examples of how<em> exponents can be used to shorten repeated multiplication</em>. The first, third, and fourth boxes all show how the repeated multiplication of 2, 3, and 5 can all be abbreviated as 2^4, 3^2 and 5^3. The only expression which doesn't belong is 3+3+3+3=3(4), because it's showing how repeated <em>addition</em> can be shortened to <em>multiplication</em>.

7 0
3 years ago
A bathroom shower streams
antiseptic1488 [7]

Answer:

Step-by-step explanation:

7 0
3 years ago
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