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3 years ago

Which of the following is a rational number? A.102 B.144 C.21 D.29

Mathematics

1 answer:

Cerrena [4.2K]3 years ago

7 0

Answer:

I'm pretty sure they're all rational numbers since they're all whole numbers.

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Carlt mowed 2 more lawns than rocco week for 5 weeks. Carlt mowed a total of 18 lawns. How many lawns did Rocco mow each week?

denis-greek [22]

Answer: 1.6 lawns a week

Step-by-step explanation:

Carlt mowed 2 more lawns than Rocco every week for 5 weeks.

This means that the number of lawns he mowed more than Rocco is:

= 2 * 5

= 10 lawns

If Carlt mowed 18 lawns in those 5 weeks then Rocco mowed:

= 18 - 10

= 8 lawns

Lawns mowed per week by Rocco:

= 8/5

= 1.6 lawns a week

4 0

3 years ago

In order to join a dancing club there is a $30 startup fee and a $4 monthly fee. write an equation in slope-intercept form that

kvv77 [185]

Y=M(x)+B
Y=4+30
4 is your slope; Y-intercept is 30

6 0

3 years ago

What is the equation in point-slope form of the line that passes through (-9, 12) with a slope of 5/6?

Hitman42 [59]

Answer:

$\large\boxed{y-12=\dfrac{5}{6}(x+9)}$

Step-by-step explanation:

The point-slope form of an equation of a line:

$y-y_1=m(x-x_1)$

m - slope

(x₁, y₁) - point on a line

We have

$m=\dfrac{5}{6},\ (-9,\ 12)\to x_1=-9,\ y_1=12$

Substitute:

$y-12=\dfrac{5}{6}(x-(-9))\\\\y-12=\dfrac{5}{6}(x+9)$

6 0

3 years ago

The Greater Pittsburgh Area Chamber of Commerce wants to estimate the mean time workers who are employed in the downtown area sp

Valentin [98]

Answer:

98% Confidence interval: (31.74,38.4)

Step-by-step explanation:

We are given the following data set:

29, 38, 38, 33, 38, 21, 45, 34, 40, 37, 37, 42, 30, 29, 35

Formula:

$\text{Standard Deviation} = \sqrt{\displaystyle\frac{\sum (x_i -\bar{x})^2}{n-1}}$

where $x_i$ are data points, $\bar{x}$ is the mean and n is the number of observations.

$Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}$

$Mean =\displaystyle\frac{526}{15} = 35.07$

Sum of squares of differences = 506.93

$S.D = \sqrt{\displaystyle\frac{506.93}{14}} = 6.02$

98% Confidence interval:

$\bar{x} \pm t_{critical}\displaystyle\frac{s}{\sqrt{n}}$

Putting the values, we get,

$t_{critical}\text{ at degree of freedom 14 and}~\alpha_{0.02} = \pm 2.145$

$35.07 \pm 2.145(\frac{6.02}{\sqrt{15}} ) = 35.07 \pm 3.33 = (31.74,38.4)$

Thus, there is 98% confidence that the population mean number of minutes spent traveling by workers is between 31.74 mins and 38.40

4 0

3 years ago

If you multiplied a number by 0.5, the result would be

Ghella [55]

Either a whole number or a decimal (has .5 in it). It truly depends on the number that it is being multiplied.

7 0

3 years ago