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kvasek [131]
2 years ago
8

Could someone help me with this?

Mathematics
1 answer:
MaRussiya [10]2 years ago
7 0

Answer: o well i dont really knwo

Step-by-step explanation:

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Do in five minutes please help me out I will give you points if you help me out thank you
Margaret [11]

Answer:

sorry dude no clue

Step-by-step explanation:

8 0
3 years ago
A conical tent has a radius of 10.4 ft and a height of 8.4 ft. Doubling which dimensions will quadruple the volume of the tent?
avanturin [10]

Answer: Doubling the radius.

Step-by-step explanation:

The volume of a cone can be found with the following formula:

V=\frac{1}{3}\pi r^2h

Where "r" is the radius and "h" is the height of the cone.

Let's find the volume of the conical tent with a radius of 10.4 feet and a height of 8.4 feet.

Identifiying that:

r=10.4\ ft\\\\h=8.4\ ft

You get this volume:

V_1=\frac{1}{3}\pi (10.4\ ft)^2(8.4\ ft)\\\\V_1=951.43\ ft^3

If you double the radius, the volume of the conical tent will be:

V_2=\frac{1}{3}\pi (2*10.4\ ft)^2(8.4\ ft)\\\\V_2=3,805.70\ ft^3

When you divide both volumes, you get:

\frac{3,805.70\ ft^3}{951.43\ ft^3}=4

Therefore, doubling the radius will quadruple the volume of the tent.

5 0
2 years ago
Simplify. (y3)5 · y4
ICE Princess25 [194]

y^3 * 5 * y^4

= 5y^(3+4)

= 5y^7 answer

8 0
2 years ago
Read 2 more answers
Kiara downloaded 264 pictures from her cell phone to her computer. These pictures took up 528 megabytes of space on her computer
Anettt [7]

Answer: 70

Step-by-step explanation: 528/264 * 35 = 70

6 0
3 years ago
Read 2 more answers
The data below represent the weight, in kilograms, of 15 containers shipped from
Nikolay [14]

Answer:

(A) Maximum = 100 kg.

(B) Lower quartile = 55 kg.

(C) Minimum = 45 kg.

(D) Upper quartile = 93 kg.

(E) Median = 81 kg.

Step-by-step explanation:

A box-plot, also known as a box and whisker plot is a method to demonstrate the distribution of a data-set based on the following 5 number summary,

  1. Minimum (shown at the bottom of the chart)
  2. First Quartile (shown by the bottom line of the box)
  3. Median (or the second quartile) (shown as a line in the center of the box)
  4. Third Quartile (shown by the top line of the box)
  5. Maximum (shown at the top of the chart).

The data provided for the weight, in kilograms, of 15 containers shipped from  a factory in one week is as follows:

S = {45, 51, 53, 55, 55, 65, 75, 81, 84, 87, 93, 93, 95, 96, 100}

The data is already arranged in ascending order.

The maximum value is:

Maximum = 100 kg.

The first quartile is the median value of the first half of the data.

The first half of the data is:

S₁ = {45, 51, 53, 55, 55, 65, 75}

The median of this data set is the middle value, i.e. 4th value.

So, the  first quartile is:

Lower quartile = 55 kg.

The minimum value is:

Minimum = 45 kg.

The third quartile is the median value of the second half of the data.

The second half of the data is:

S₂ = {84, 87, 93, 93, 95, 96, 100}

The median of this data set is the middle value, i.e. 4th value.

So, the third quartile is:

Upper quartile = 93 kg.

The The median of the data set is the middle value, i.e. the 8th value.

Median = 81 kg.

6 0
3 years ago
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