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Ksju [112]
3 years ago
11

If anyone has done this can you help me out?

Chemistry
1 answer:
Elena L [17]3 years ago
6 0

Answer:

05.01 Electromagnetic Spectrum

Name: Dayanara Chavez

Date: 2/23/2021

Electromagnetic Energy Example One

Activity: Microwave

Type of electromagnetic energy: Microwaves are a form of "electromagnetic" radiation

Picture:

Description of use: They are waves of electrical and magnetic energy moving together through space. Electromagnetic radiation spans a broad spectrum from very long radio waves to very short gamma rays.

Electromagnetic Energy Example Two

Activity: Cellphone

Type of electromagnetic energy: Radiofrequency

Picture:

Description of use: What type of energy does a cellular phone use? Cell phones (and cell phone towers) use low-powered radiofrequency (RF) energy, a type of non-ionizing radiation. Non-ionizing radiation is not able to break the chemical bonds in your body.

Electromagnetic Energy Example Three

Activity: AM and FM radio

Type of electromagnetic energy: Electromagnetic radiation

Picture:

Description of use: Radio waves are a type of electromagnetic radiation best-known for their use in communication technologies, such as television, mobile phones and radios.

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1.20 x 10^22 molecules NaOH to gram
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Answer:

\boxed {\boxed {\sf 0.797 \ g \ NaOH}}

Explanation:

<u>1. Convert Molecules to Moles</u>

First, we must convert molecules to moles using Avogadro's Number: 6.022*10²³. This tells us the number of particles in 1 mole of a substance. In this case, the particles are molecules of sodium hydroxide.

\frac {6.022*10^{23} \ molecules \ NaOH} {1 \ mol \ NaOH}}

Multiply by the given number of molecules.

1.20*10^{22} \ molecules \ NaOH *\frac {6.022*10^{23} \ molecules \ NaOH} {1 \ mol \ NaOH}}

Flip the fraction so the molecules cancel out.

1.20*10^{22} \ molecules \ NaOH *\frac {1 \ mol \ NaOH} {6.022*10^{23} \ molecules \ NaOH}}

1.20*10^{22}  *\frac {1 \ mol \ NaOH} {6.022*10^{23}}}

\frac {1.20*10^{22} \ mol \ NaOH} {6.022*10^{23}}}

0.0199269345732 \ mol \ NaOH

<u>2. Convert Moles to Grams</u>

Next, we convert moles to grams using the molar mass.

We must calculate the molar mass using the values on the Periodic Table. Look up each individual element.

  • Na: 22.9897693 g/mol
  • O: 15.999 g/mol
  • H: 1.008 g/mol

Since the formula has no subscripts, we can simply add the molar masses.

  • NaOH: 22.9897693+15.999+1.008=39.9967693 g/mol

Use this as a ratio.

\frac {39.9967693 \ g  \ NaOH }{1 \ mol \ NaOH}

Multiply by the number of moles we calculated.

0.0199269345732 \ mol \ NaOH*\frac {39.9967693 \ g  \ NaOH }{1 \ mol \ NaOH}

The moles of sodium hydroxide cancel.

0.0199269345732 *\frac {39.9967693 \ g  \ NaOH }{1}

0.0199269345732 *39.9967693 \ g  \ NaOH

0.79701300498 \ g \ NaOH

The original measurement of molecules has 3 significant figures, so our answer must have the same. For the number we calculated, that is the thousandth place. The 0 tells us to leave the 7 in the hundredth place.

0.797 \ g \ NaOH

1.20*10²² molecules of sodium hydroxide is approximately 0.797 grams.

4 0
3 years ago
If equal amounts of silver ion are added to silver bromide and silver chloride, why does the bromide mixture precipitate first?
VARVARA [1.3K]
Answer is: precipitation requires fewer Ag⁺<span> ions in AgBr than in AgCl.
Chemical reactions:
Ksp(KBr) = 5,3</span>·10⁻¹³.
Ksp(KCl) = 1,8·10⁻¹⁰.
Ksp is <span>solubility product constant. The higher the Ksp value, substance is more soluble. KBr has lower Ksp, so it is easier to form precipitant of KBr than KCl.</span>
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(2 Question 6 Without modifying the apparatus, how could the reliability of the results be increased?​
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Explanation:

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