<u>Answer:</u>
<u>When an alkyl benzene is heated with strong oxidizing asgents like acidic or alkline KMnO4</u>
<u> or acidified K2Cr2O7</u>
<u>, etc. gives aromatic carboxyllic acid. The alkyl side chain gets oxidised to −COOH</u>
<u> group irrespective of the size of the chain.</u>
Explanation:
Answer:
Al(NO₃)₃ > KI > HF > CH₃OH
Explanation:
The electrical conductivities of the solutions will depend on the concentration of ions in solution.
Al(NO₃)₃ solution contains 0.1 M of Al³⁺ ions and 0.3 M of NO₃⁻ ions
KI solution contains 0.1 M of K⁺ ions and 0.1 M of I⁻ ions
HF solution contains less than 0.1 M of H⁺ ions and less then 0.1 M of F⁻ ions, because the HF acid will not dissociate completely
CH₃OH practically it does not dissociate, so in the solution will not be electrical conductive (comparative with the other solutions)
The solutions in order of decreasing intensity of the bulb are ranked as following:
Al(NO₃)₃ > KI > HF > CH₃OH
The first one is 32mL and the second one is 2.62 and I think it’s grams/mL I’m not for sure about the letters on the second one
