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attashe74 [19]
3 years ago
13

Someone plz help me I can’t get out

Chemistry
2 answers:
kotegsom [21]3 years ago
6 0

Answer:if you can't close the tabs I suggest try and restart the computer

Explanation:

horrorfan [7]3 years ago
3 0

Answer:

Refresh your page or if that doesn't work, close your tab and try to click it again or restart your pc

Explanation:

You might be interested in
What is the purpose of cryolite during electrolysis??​
Effectus [21]

Answer:

The purpose of cryolite during electrolysis is that the mixture of cryolite and aluminium oxide has a lower melting point than pure aluminium oxide. Molten cryolite serves as a solvent for the molten aluminium oxide and increases the conductivity of the solution.

5 0
4 years ago
Read 2 more answers
How many moles of methane are in 7.31x10^25 molecules?
lana [24]

Answer:

121.37 moles.

Explanation:

Always one mole of any molecule contains Avogadro number of molecules.

So one mole of methane contains 6.023*10^23 molecules.

Now we need number of moles of methane in 7.31*10^25 molecules.

This is just cross multiplication stuff.

6.023*10^23 molecules —————- 1 mole

7.31*10^25 molecules ——————- ?

= (7.31*10^25) / (6.023*10^23)

= 121.37 moles.

8 0
3 years ago
Complete the sentences to explain why the lattice energy of potassium bromide is more exothermic than the lattice energy of rubi
Natali5045456 [20]
The lattice energy is the amount of energy released when the ions that make up a crystal lattice are brought together. Now, this energy is dependent on the charge concentration of these ions. Both potassium and rubidium form ions with a +1 charge, while bromine and iodine form ions with -1 charge. However, because potassium and bromine are smaller than rubidium and iodine respectively, the charge is more concentrated. Therefore, more energy is released when potassium and bromine are brought together. 
5 0
3 years ago
Read 2 more answers
Please answers the question​
frozen [14]
That is correct hope that helps
8 0
3 years ago
A solution of HCOOH has 0.16M HCOOH at equilibrium. The Ka for HCOOH is 1.8×10−4. What is the pH of this solution at equilibrium
kotykmax [81]

Answer:

pH=2.28

Explanation:

Hello,

In this case, for the acid dissociation of formic acid (HCOOH) we have:

HCOOH(aq)\rightarrow H^+(aq)+HCOO^-(aq)

Whose equilibrium expression is:

Ka=\frac{[H^+][HCOO^-]}{[HCOOH]}

That in terms of the reaction extent is:

1.8x10^{-4}=\frac{x*x}{0.16-x}

Thus, solving for x which is also equal to the concentration of hydrogen ions we obtain:

x=0.00528M

[H^+]=0.00528M

Then, as the pH is computed as:

pH=-log([H^+])

The pH turns out:

pH=-log(0.00528M)\\\\pH=2.28

Regards.

7 0
4 years ago
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