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oee [108]
3 years ago
7

Which statement describes the translation from the graph of y = |x| to the graph of y = | x - 1 | -5

Mathematics
1 answer:
Doss [256]3 years ago
3 0

Answer:

Step-by-step explanation:

Shift 1 unit right and 5 units down

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How many x-intercepts appear on the graph of this polynomial function? f (x) = x Superscript 4 Baseline minus 5 x squared 1 x-in
Brut [27]

Answer:

3 x-intercepts

Step-by-step explanation:

f(x) = x⁴ - 5x²

6 0
3 years ago
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Which triangles are similar?
lara31 [8.8K]
I’m pretty sure it would be a and b
3 0
3 years ago
2(x-3)=7x-31<br><br> 3x-2 (x+5)=-3+18<br><br> Please show your work
vredina [299]
2(x-3)=7x-31
2x-6=7x-31
-7x    -7x
----------------
-5x-6=-31
     +6   +6
--------------
-5x=-25
Divide by -5
x=5

3x-2(x+5)=-3+18
                     15
3x-2(x+5)=15
3x-2x-10=15
x-10=15               
 +10 +10
--------------
x=25
3 0
3 years ago
In his boat, Sheldon can travel 45 mi downstream in the same time that it takes to travel 9 mi upstream. If the rate of the curr
Nataliya [291]

Answer:

9 mph

Step-by-step explanation:

-let x be the speed of current and t be time. The speed equation for both directions can then be represented as:

Speed=\frac{Distance}{Time}\\\\\#Upstream\\(u-6)t=9\\\\\#Donwstream\\\\(u+6)t=45

#Since t is equal in both, we can do away with t.

#We the divide the downstream equation by the upstream equation as:

\frac{u+6}{u-6}=\frac{45}{9}\\\\(u+6)=5(u-6)\\\\u+6=5u-30\\\\4u=36\\\\u=9

Hence, the boat's speed in still water is  9 mph

7 0
4 years ago
Special Right Trianglws
Masteriza [31]

Answer:

x = 2\sqrt7

y = 2\sqrt7

Step-by-step explanation:

Hello!

This is a right isosceles triangle (45°-45°-90°). You can solve for the missing angle by simply subtracting 45° and 90° from 180° (sum of angles in a triangle equals 180°)

Since the triangle is isosceles, x and y are congruent because they are the legs opposite to the congruent angles.

In a right isosceles triangle, the hypotenuse is always the measure of one leg multiplied by \sqrt2.

So, let's use leg y, y\sqrt2 = 2\sqrt{14}

Solve for y:

y\sqrt2 = 2\sqrt{14}\\\\y = $\frac{2\sqrt{14}}{\sqrt2}$\\\\y = 2\sqrt7

y = 2\sqrt7, which means that x is also 2\sqrt7

3 0
3 years ago
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