For the first figure, the geometric figure used in the construction that is shown is the intersection of the angle bisectors of the triangle is the center of the inscribed circle.
For the second figure, the construction of the above figure in the circle represents how to find the intersection of the perpendicular bisectors of triangle ABC.
For the third figure, the statement that is demonstrated in the in line P intersecting line m perpendicularly is the set of points equidistant from the endpoints of a line segment is the perpendicular bisector of the segment.
Answer:
Neon: 0
Oxide: -2
Copper: 2
Tin: 0
Step-by-step explanation: To solve you must add/subtract the numbers to get the charge, for example if its -30 charge from electrons and 10 charge from protons, -30 + 10 = -20 therefore the charge is -20
Answer:
1/3^2
Im trying to earn my brainliest..so if you don't mind :)
There are 2 variables in this problem. One variable is the class number and other variable is the participation in extracurricular activities. Each variable has further two categories. There are two classes: Class 10 and 11. And students either participate or do not participate in extracurricular activities, which makes 2 categories.
The best approach to solve this question is to build a table and start entering the given information in it. When the given data has been entered fill the rest on basis of the data you have.
18 students from grade 11 participate in at least one Extracurricular activities. This means the rest students i.e. 22 students from grade 11 do not participate in Extracurricular activities.
32 students from grade 10 participate in at least one Extracurricular activities. This means total students who participate in at least one Extracurricular activities are 18 + 32 = 50 students.
The rest 50 students do not participate in at least one Extracurricular activities. From these 22 are from class 11. So the rest i.e. 28 are from class 10.
Answer:
2/3
Step-by-step explanation:
Convert the fractions to decimals.
2/3 = 0.666
4/5 = 0.8
14/18 = 0.777
34/50 = 0.68
From the decimals, 0.666 is the only option which falls between 0.5 and 0.75.
