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2 years ago

-5x - 3y + z=-4 -2x - 2y + 2z = 4 Z=x+5

Mathematics

1 answer:

Len [333]2 years ago

3 0

Answer:{x,y,z} = {85/24,-1/6,25/24}

Step-by-step explanation:

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List the first 10 multiples for each number 3,4,7

notka56 [123]

Answer:

Step-by-step explanation:

3- 3, 6, 9, 12, 15, 18, 21, 24, 27, 30

4- 4, 8, 12, 16, 20, 24, 28, 32, 36, 40

7- 7, 14, 21, 28, 35, 42, 49, 56, 63, 70

HOPE IT HELPED

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2 years ago

Read 2 more answers

Due to a leak, the amount of water in a pool is decreasing by 5858 gal every hour.

Dafna1 [17]

Here is the solution to the given problem above.
Given the the amount of water in a pool is decreasing 5/8 gallon every hour.
And what would be the change in the number of gallons after 3/4 hour. So what we are going to do is just to multiply 5/8 by 3/4. And the result would be 15/32. The total change in the number of gallons of water in the pool after 3/4 hour would be 15/32 gallons.

4 0

2 years ago

Lana needs to find the. to find this, she could list. of both numbers, and circle each bumber that appeas in both lists. she sho

strojnjashka [21]

U still need help or nah?

7 0

2 years ago

Jack has a summer job caddying at a golf course. Jack earns $120

Alina [70]

1200 as you would round it down to 100 a week so you would do 100x12

5 0

3 years ago

A 90 percent confidence interval is to be created to estimate the proportion of television viewers in a certain area who favor m

Dominik [7]

Answer:

This means that the first interval, with 9000 viewers, is 3 times as narrower as the second interval, with 1000 viewers.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

The width of the interval is:

$W = 2z\sqrt{\frac{\pi(1-\pi)}{n}}$

In this sample:

Two 90% intervals, with different lenghts. So both have the same values for z an $\pi$

Interval A:

9000 viewers.

So the width is

$W_{A} = 2z\sqrt{\frac{\pi(1-\pi)}{9000}}$

Interval B:

100 viewers

So the width is

$W_{B} = 2z\sqrt{\frac{\pi(1-\pi)}{1000}}$

Relationship between the widths:

$R = \frac{W_{A}}{W_{B}} = \frac{2z\sqrt{\frac{\pi(1-\pi)}{9000}}}{2z\sqrt{\frac{\pi(1-\pi)}{1000}}} = \frac{\sqrt{1000}}{\sqrt{9000}} = \frac{\sqrt{1}}{\sqrt{9}} = \frac{1}{3}$

This means that the first interval, with 9000 viewers, is 3 times as narrower as the second interval, with 1000 viewers.

8 0

2 years ago