2xp+3y=10 Solve for x
1 answer:
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Answer:
min at (3, 0 )
Step-by-step explanation:
given a quadratic in standard form
y = ax² + bx + c ( a ≠ 0 )
then the x- coordinate of the vertex is
= -
y = (x - 3)² = x² - 6x + 9 ← in standard form
with a = 1 and b = - 6 , then
= -
= 3
substitute x = 3 into the equation for corresponding value of y
y = (3 - 3)² = 0² = 0
vertex = (3, 0 )
• if a > 0 then vertex is minimum
• if a < 0 then vertex is maximum
here a = 1 > 0 then (3, 0 ) is a minimum