Given that the number rolled is odd, it can be 1, 3, or 5 = 3 possibilities.
Only one of the possibilities is success . . . rolling a 3 .
So the probability of success is 1/3 = 33 and 1/3 percent .
Answer:
thank you
Step-by-step explanation:
The desired number is the difference between the number of messages sent by the 16th day and the number sent by the 9th day:
... n = t(16) - t(9)
... n = (40×√16) - (40×√9)
... n = 40×(4 - 3) = 40
40 text messages were sent between the ninth and sixteenth day of the month.
Answer:
As per the question, we need to convert product of sum into sum of product,
Given:
(A' +B+C')(A'+C'+D)(B'+D'),
At first, we will solve to parenthesis,
= (A'+C'+BD) (B'+D')
As per the Rule, (A+B)(A+C) = A+BC, In our case if we assume X = A'+C', then,
(A' +B+C')(A'+C'+D) = (A'+C'+B)(A'+C'+D) = (A'+C'+BD)
Now,
= (A'+C'+BD) (B'+D') = A'B' + A'D' + C'B' +C'D' +BDB' +BDD"
As we know that AA' = 0, it mean
=A'B'+A'D'+C'B'+C'D'+D*0+B0
=A'B'+A'D'+C'B'+C'D' as B * 0 and D*0 = 0
Finally, minimum sum of product boolean expression is
A''B'+A'D'+C'B'+C'D'
=
