Answer:
Owwwww would be a good time
Answer:
4
Step-by-step explanation:
A simple matter of using Pythagoras. The hypotenuse is the ladder, and one of the legs is the wall, and we have to figure out the value of the other leg.
The Pythagorean formuda is (hypotenuse = a): a² + b² = c² (b and c are the other sides)
applying the values: a = 5 and b or c is 3 (I'll put b = 3)
5² = 3² + c²
25 = 9 + c²
25 - 9 = c²
16 = c²
√16 = c
4 = c
c = 4
Answer:
Step-by-step explanation:
8p+3f=10.39
5p+4f=10.51
subtract
3p-f=-0.12
f=3p+0.12
8p+3(3p+0.12)=10.39
17p=10.39-0.36
17p=10.03
p=10.03/17=0.59
f=3×0.59+0.12=1.77+0.12=1.89 $
or 40 p+15f-40p-32f=51.95-84.08
-17f=-32.13
f=1.89 $
Answer:
yes, the student who has 8 pets.
Step-by-step explanation:
the majority of the class has between 0-4 pets leaving the student with 8 to be the "outlier"
Formula is π * r^2
π = about 3.14 and the radius is half of the diameter so 28/2 = 14
3.14 * 14^2 = 615.44
B
