Let D be dogs and C be cats
<em>dogs, d, is initially five less than twice the number of cats, c</em>
D + 5 = 2C
<em>If she decides to add three more of each, the ratio of cats to dogs will be</em>
D + 8 = 2C + 3
<em>Could Bea's Pet Shop initially have 15 cats and 20 dogs?</em>
Simply plug in the numbers
20 + 5 = 2(15)
This is clearly not true: 25 does not equal 30
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I believe that it's (1,3)
(tip: with these problems, try to use desmos.com)
The mean = (3+1+2+2+2) / 5 = 10/5 = 2
subtract mean from each of the values
gives 1 -1 0 0 0
MAD = (1^1 + (-1)^2) / 5 = 2/5 = 0.4
A is the correct choice.
Answer:3.6
Step-by-step explanation: your just duh and duh