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Alona [7]
3 years ago
7

Can you simplify 81/10? If you can what is it?

Mathematics
2 answers:
Irina-Kira [14]3 years ago
7 0
Yes, 81/10 can be simplified. Since it is an improper fraction, since its numerator is larger than its denominator, that means it can be converted to a mixed number.

First, find how many times the numerator goes into the denominator.
81 goes into 10 8 times, with a remainder of 1.
This means 81/10 is equal to 8 and 1/10.

As a mixed number, 81/10 is 8 and 1/10.

To further simplify this, you can convert it to an integer.
First, convert 1/10 to a decimal.
1/10 = 0.1
Then, add this decimal to the whole number, 8.
8 + 0.1 = 8.1
This means 8 and 1/10 is equal to 8.1.

As an integer, 8 and 1/10, which is simplified from 81/10, is equal to 8.1.

Answers:
81/10 = 8 and 1/10 = 8.1

Hope this helps!
Maksim231197 [3]3 years ago
3 0
The answer would be 8 1/10.
81 divided by 10 = 8r.1 (your whole number)
Your remainder then goes as your numerator.

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Answer:

<h2>c. x = -4 or x = 9</h2>

Step-by-step explanation:

\dfrac{4}{x}+\dfrac{4}{x^2-9}=\dfrac{3}{x-3}

Domain:

x\neq0\ \wedge\ x^2-9\neq0\ \wedge\ x-3\neq0\\\\x\neq0\ \wedge\ x\neq\pm3

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\dfrac{4}{x}+\dfrac{4}{x^2-3^2}=\dfrac{3}{x-3}

use <em>(a - b)(a + b) = a² - b²</em>

\dfrac{4}{x}+\dfrac{4}{(x-3)(x+3)}=\dfrac{3}{x-3}

multiply both sides by (x - 3) ≠ 0

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cancel (x - 3)

\dfrac{4(x-3)}{x}+\dfrac{4}{x+3}=3

subtract \frac{4(x-3)}{x} from both sides

\dfrac{4}{x+3}=3-\dfrac{4(x-3)}{x}\\\\\dfrac{4}{x+3}=\dfrac{3x}{x}-\dfrac{(4)(x)+(4)(-3)}{x}\\\\\dfrac{4}{x+3}=\dfrac{3x-\bigg(4x-12\bigg)}{x}\\\\\dfrac{4}{x+3}=\dfrac{3x-4x-(-12)}{x}\\\\\dfrac{4}{x+3}=\dfrac{-x+12}{x}

cross multiply

(4)(x)=(x+3)(-x+12)

use FOIL

4x=(x)(-x)+(x)(12)+(3)(-x)+(3)(12)\\\\4x=-x^2+12x-3x+36

subtract 4x from both sides

0=-x^2+12x-3x+36-4x

combine like terms

0=-x^2+(12x-3x-4x)+36\\\\0=-x^2+5x+36

change the signs

x^2-5x-36=0\\\\x^2-9x+4x-36=0\\\\x(x-9)+4(x-9)=0\\\\(x-9)(x+4)=0

The product is 0 if one of the factors is 0. Therefore:

x-9=0\ \vee\ x+4=0

x-9=0            <em>add 9 to both sides</em>

x=9\in D

x+4=0          <em>subtract 4 from both sides</em>

x=-4\in D

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