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nadezda [96]
3 years ago
10

In the first fifth of the season the Madrigals played 12 games.

Mathematics
1 answer:
VladimirAG [237]3 years ago
7 0

Answer:

A

Step-by-step explanation:

it is not asking anything about won games you just have to take 12x5 to get answer to A

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The number of trees in a rainforest decreases each month by 0.5%. The forest currently has 2.5 billion trees. Which expression r
Blababa [14]

Answer:

y=2.5*10^9(0.005^{12 0}) \\\\

Step-by-step explanation:

The above question is in the form of an exponential decay. The equation for an exponential decay is given by:

y=ab^x

where y and x are variables, b < 1, a is the initial value of y (that is the value of y when x = 0).

Let y represent the number of trees left and x represent the number of months. Given that there is currently 2.5 billion trees, therefore a = 2.5 * 10⁹, b = 0.5% = 0.005. The equations becomes:

y=2.5*10^9(0.005^x)\\\\After\ ten\ years(x=10*12\ months=120\ months):\\\\y=2.5*10^9(0.005^{12 0}) \\\\

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3 years ago
Please help math
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8 0
3 years ago
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Jackson recorded the growth of a plant over 10 weeks. The equation y=0.25+4 represents the height y in inches over time x in wee
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Answer:

Step-by-step explanation:

Allow me to rewrite your question and hope it will fit the original one:

<em>Jackson recorded the growth of a plant over 10 weeks. The equation </em><em>y=0.25x+4</em><em> represents the height y in inches over time x in weeks what does the y intercept represent In terms of the situation</em>

My answer:

As we know that y intercept is the value of y at the point where the line crosses the y axis (the value of x =0)

So in this situation, if x= 0, it means the height of the tree (y-intercept) initially be at 4 at week 0.

Hope it will find you well.

5 0
3 years ago
Charlotte makes crepes using 5/8 cup of milk for every 1/2 cup of flour. She wants to know the amount of milk uses per cup of fl
const2013 [10]

Answer:1 1/4

Step-by-step explanation:

3 0
2 years ago
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The probability that a professor arrives on time is 0.8 and the probability that a student arrives on time is 0.6. Assuming thes
saul85 [17]

Answer:

a)0.08  , b)0.4  , C) i)0.84  , ii)0.56

Step-by-step explanation:

Given data

P(A) =  professor arrives on time

P(A) = 0.8

P(B) =  Student aarive on time

P(B) = 0.6

According to the question A & B are Independent  

P(A∩B) = P(A) . P(B)

Therefore  

{A}' & {B}' is also independent

{A}' = 1-0.8 = 0.2

{B}' = 1-0.6 = 0.4

part a)

Probability of both student and the professor are late

P(A'∩B') = P(A') . P(B')  (only for independent cases)

= 0.2 x 0.4

= 0.08

Part b)

The probability that the student is late given that the professor is on time

P(\frac{B'}{A}) = \frac{P(B'\cap A)}{P(A)} = \frac{0.4\times 0.8}{0.8} = 0.4

Part c)

Assume the events are not independent

Given Data

P(\frac{{A}'}{{B}'}) = 0.4

=\frac{P({A}'\cap {B}')}{P({B}')} = 0.4

P({A}'\cap {B}') = 0.4 x P({B}')

= 0.4 x 0.4 = 0.16

P({A}'\cap {B}') = 0.16

i)

The probability that at least one of them is on time

P(A\cup B) = 1- P({A}'\cap {B}')  

=  1 - 0.16 = 0.84

ii)The probability that they are both on time

P(A\cap  B) = 1 - P({A}'\cup {B}') = 1 - [P({A}')+P({B}') - P({A}'\cap {B}')]

= 1 - [0.2+0.4-0.16] = 1-0.44 = 0.56

6 0
2 years ago
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