PATH INDEPENDENCE? 13-19 from Check, and if independent, integrate from (0, 0, 0) to (a, b, c) 13. 2e (x cos 2y dx - sin 2y dy)
1 answer:
The integral is path-independent if there is a scalar function
whose gradient is
![\nabla f=(2e^x\cos2y,-\sin2y)](https://tex.z-dn.net/?f=%5Cnabla%20f%3D%282e%5Ex%5Ccos2y%2C-%5Csin2y%29)
(at least, that's what it looks like the given integrand is)
Then
![\dfrac{\partial f}{\partial x}=2e^x\cos 2y\implies f(x,y)=2e^x\cos2y+g(y)](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Cpartial%20f%7D%7B%5Cpartial%20x%7D%3D2e%5Ex%5Ccos%202y%5Cimplies%20f%28x%2Cy%29%3D2e%5Ex%5Ccos2y%2Bg%28y%29)
Differentiating both sides with respect to
gives
![\dfrac{\partial f}{\partial y}=-4e^x\sin 2y\neq-\sin2y](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Cpartial%20f%7D%7B%5Cpartial%20y%7D%3D-4e%5Ex%5Csin%202y%5Cneq-%5Csin2y)
so the line integral *is* dependent on the path. (again, assuming what I've written above actually reflects what the question is asking)
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