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Vilka [71]
4 years ago
11

The number 1/5 is which type of number?

Mathematics
2 answers:
vladimir1956 [14]4 years ago
7 0
D. Rational. A way you can tell is that 1/5 is a fraction and a fraction is a RATIO, which means it’s a RATIOnal number
Ksju [112]4 years ago
3 0
the answer is

d. rational
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Here are some numbers
KengaRu [80]

Answer:

11,18,25

Step-by-step explanation:

add 7

7 0
3 years ago
What is the product of the binomials (4a – 1) and (2b + 3)?
galben [10]

Answer:

D. 8ab+12a-2b-3

Step-by-step explanation:

You are basically combining like terms

8 0
3 years ago
Read 2 more answers
Could someone help me with this please!
sertanlavr [38]
Angles 1, 3, and 4 make up a straight line.
Thus, 3x + 90 + 3x - 6 = 180 (angle sum of straight line)
6x - 6 = 90
6x = 96

x = 16
Now angle 1 becomes 3(16) = 48
Angle 1, 2, and 3 also make up a straight line.
Thus, angle 2 + 48 + 90 = 180
angle 2 + 138 = 180
angle 2, therefore, becomes 42. In essence, (A)
6 0
3 years ago
Read 2 more answers
If b equals 4 and = 7 what is ad
Elodia [21]

Answer:

3

Step-by-step explanation:

I gussed but I'm not sure

3 0
3 years ago
Can someone please help me??
dmitriy555 [2]

Answer:

I is clear that, the linear equation 5x+12=5x-7 has no solution.

Step-by-step explanation:

<u>Checking the first option:</u>

\frac{2}{3}\left(9x+6\right)=6x+4

6x+4=6x+4

\mathrm{Subtract\:}4\mathrm{\:from\:both\:sides}

6x+4-4=6x+4-4

6x=6x

\mathrm{Subtract\:}6x\mathrm{\:from\:both\:sides}

6x-6x=6x-6x

0=0

\mathrm{Both\:sides\:are\:equal}

\mathrm{True\:for\:all}\:x

<u>Checking the 2nd option:</u>

5x+12=5x-7

\mathrm{Subtract\:}5x\mathrm{\:from\:both\:sides}

5x+12-5x=5x-7-5x

\mathrm{Simplify}

12=-7

\mathrm{The\:sides\:are\:not\:equal}

\mathrm{No\:Solution}

<u>Checking the 3rd option:</u>

4x+7=3x+7

\mathrm{Subtract\:}7\mathrm{\:from\:both\:sides}

4x+7-7=3x+7-7

\mathrm{Simplify}

4x=3x

\mathrm{Subtract\:}3x\mathrm{\:from\:both\:sides}

4x-3x=3x-3x

\mathrm{Simplify}

x=0

<u>Checking the 4th option:</u>

-3\left(2x-5\right)=15-6x

\mathrm{Subtract\:}15\mathrm{\:from\:both\:sides}

-6x+15-15=15-6x-15

\mathrm{Simplify}\

-6x=-6x

\mathrm{Add\:}6x\mathrm{\:to\:both\:sides}

-6x+6x=-6x+6x

\mathrm{Simplify}

\mathrm{Both\:sides\:are\:equal}

\mathrm{True\:for\:all}\:x

Result:

Therefore, from the above calculations it is clear that, the linear equation

5x+12=5x-7 has no solution.

4 0
3 years ago
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