What is the difference between dependent and independent?

Mathematics

1 answer:

andrey2020 [161]3 years ago

5 0

independent is =solo . dependent= you are depending of others.

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Find the given derivative by finding the first few derivatives and observing the pattern that occurs. d103 dx103 (sin(x))

aleksandrvk [35]

To find $\frac{d^{103}}{dx^{103}} \left(\sin{(x)}\right)$ , we find the first few derivatives and observe the pattern that occurs.

$\frac{d}{dx} (\sin{(x)})=\cos{(x)} \\ \\ \frac{d^2}{dx^2} (\sin{(x)})= \frac{d}{dx} (\cos{(x)})=-\sin{(x)} \\ \\ \frac{d^3}{dx^3} (\sin{(x)})= -\frac{d}{dx} (\sin{(x)})=-\cos{(x)} \\ \\ \frac{d^4}{dx^4} (\sin{(x)})= -\frac{d}{dx} (\cos{(x)})=-(-\sin{(x)})=\sin{(x)} \\ \\ \frac{d^5}{dx^5} (\sin{(x)})= \frac{d}{dx} (\sin{(x)})=\cos{(x)}$

As can be seen above, it can be seen that the continuos derivative of sin (x) is a sequence which repeats after every four terms.

Thus,

$\frac{d^{103}}{dx^{103}} \left(\sin{(x)}\right)= \frac{d^{4(25)+3}}{dx^{4(25)+3}} \left(\sin{(x)}\right) \\ \\ = \frac{d^3}{dx^3} \left(\sin{(x)}\right)=-\cos{(x)}$

Therefore,

$\frac{d^{103}}{dx^{103}} \left(\sin{(x)}\right)=-\cos{(x)}$ .

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nataly862011 [7]

B. Midpoint of a line segment

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WARRIOR [948]

X=46

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You just have to make 3x-28 and x+64 equal to each other and x would be 46.

m∠1=44

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One coin in a collection of 65 has two heads. The rest are fair. If a coin, chosen at random from the lot and then tossed, turns

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Answer:

P=1/65.

Step-by-step explanation:

We knaow that one coin in a collection of 65 has two heads. If a coin, chosen at random from the lot and then tossed, turns up heads 6 times in a row. We calculate the probability that it is the two-headed coin.

We calculate the number of possible combinations:

$C_1^{65}=\frac{65!}{1!(65-1)!}=65$

Number of favorable combinations is 1.

Therefore, the probability is

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