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Sonbull [250]
4 years ago
5

A test requires that you answer either part A or part B. Part A consists of 7 true-false questions, and part B consists of 5 mul

tiple-choice questions with one correct answer out of five. How many different completed answer sheets are possible?
Mathematics
1 answer:
jeka944 years ago
5 0

Answer: 3253

Step-by-step explanation:

Given : A test requires that you answer either part A or part B.

Part A consists of 7 true-false questions.

i.e.  there are 2 choices to answer each question.

Now, the number of ways to answer Part A : 2^7=128    (1)

Part B consists of 5 multiple-choice questions with one correct answer out of five.

i.e.  there are 5 choices to answer each question.

Now, the number of ways to answer Part B : 5^5=3125                           (2)

Now, the number of  different ways to completed answer sheets are possible=  128+3125=3253          [Add (1) and (2) ]

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Find three consecutive odd integers such that the sum of the 1st and 2nd number is 344
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Answer:

three consecutive odd integers are.

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Step-by-step explanation:

Let x be the first term of odd integer,

Therefore, the second consecutive odd integers = x+2

Similarly, the third consecutive odd integers = x+4

Given:

The sum of the first term and second term is 344.

first term + second term = 344

Here first term is x and second term is x+2.

x+(x+2)=344

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4 years ago
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I wonder if I did #9 right and I’m having trouble with #10
yaroslaw [1]
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QUESTION: Add. Write your answer as a mixed number in simplest form.

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1. Rewriting our equation with parts separated

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</span></span>2. Solving the whole number parts

<span>6+9=15

</span>3. Solving the fraction parts

<span><span>\frac{7}{9} + \frac{8}{9} = \frac{15}{9}

</span></span>4. Reducing the fraction part, 15/9,

<span><span>\frac{15}{9} = \frac{5}{3}

</span></span>5. Simplifying the fraction part, 5/3,

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</span></span>6. Combining the whole and fraction parts

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ANSWER: 16\frac{2}{3}

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