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Snowcat [4.5K]
3 years ago
15

please help! What is the empirical formula for a compound that has 1 mole of nitrogen and 2.5 moles of oxygen?

Chemistry
1 answer:
Leona [35]3 years ago
4 0

Answer:

N_{2}O_{5}

Explanation:

usually, the first step is to calculate the moles but since that is already given in the question we can move onto the next step

<u><em>least molar ratio:</em></u>

N = \frac{1}{1} = 1

O = \frac{2.5}{1} = 2.5

when the answer is in decimals we will multiply it by an integer in order to make it a whole number (in this case 2)

O = 2.5(2) = 5

in order to balance, we will also multiply the atoms of N by the same integer

N = 1(2) = 2

thus, the empirical formula is N_{2}O_{5}

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Answer:  Approximately 0.267 \frac{\text{J}}{\text{g}^{\circ}\text{C}}

===================================================

Work Shown:

We have the following variables

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note: the symbol \Delta is the uppercase Greek letter delta. It represents the difference or change in a value.

Apply those values into the formula below. Solve for c.

Q = m*c*\Delta t\\\\714 = 52*c*51.5\\\\714 = 52*51.5*c\\\\714 = 2678*c\\\\2678*c = 714\\\\c = \frac{714}{2678}\\\\c \approx 0.26661687826737\\\\c \approx 0.267\\\\

The specific heat of the unknown metal is roughly 0.267 \frac{\text{J}}{\text{g}^{\circ}\text{C}}

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