Answer:
8.90
Explanation:
Density = mass ÷ volume
D = 222.50 g ÷ 25.00
= 8.9
The density of the unknown metal is 8.90.
Hope that helps.
Answer: 1+
Justification:
The ionization energies tell the amount of energy needed to release an electron and form a ion. The first ionization energy if to loose one electron and form the ion with oxidation state 1+, the second ionization energy is the energy to loose a second electron and form the ion with oxidation state 2+, the third ionization energy is the energy to loose a third electron and form the ion with oxidation state 3+.
The low first ionization energy of element 2 shows it will lose an electron relatively easily to form the ion with oxidations state 1+.
The relatively high second ionization energy (and third too) shows that it is very difficult for this atom to loose a second electron, so it will not form an ions with oxidation state 2+. Furthermore, given the relatively high second and third ionization energies, you should think that the oxidation states 2+ and 3+ for element 2 never occurs.
Therefore, the expected oxidation state for the most common ion of element 2 is 1+.
Answer:
ScCl₂
General Formulas and Concepts:
<u>Chemistry</u>
- Reading a Periodic Table
- Reaction Prediction
- Determining Chemical Compounds
Explanation:
<u>Step 1: Define</u>
Scandium (II)
Cl
<u>Step 2: Determine Charges</u>
Sc²⁺
Cl⁻
<u>Step 3: Predict Compound</u>
<em>We need to balance out the charges so the overall charge is 0.</em>
ScCl₂
<u>Step 4: Reaction</u>
RxN: Sc²⁺ + Cl₂ → ScCl₂
Explanation:
In this experiment, carbon dioxide and water vapors combine to form H2CO3. After decomposition, the Na2CO3 had a mass of 2.86 grams. Determine ...
