Find P(A or B) if the events are disjointed. P(A) =6/25 , and P(B) =9/25 .

2 answers:

8 0

Here, "disjointed" signifiies that Event A and Event B are independent; neither outcome influences the other. In such a case, the union of A and B is given by the sum of the two probabilities P(A) and P(B).

Here, that sum is P(A or B) = 6/25 + 9/25, or 15/25, or 0.6.

kvasek [131]3 years ago

4 0

He was correct he just forgot to simplify it which it would be 3/5

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In a standard normal distribution, what z value corresponds to 17% of the data between the mean and the z value?

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You're looking for a value $z$ such that

$\mathbb P(0$

Because the distribution is symmetric, the value of $z$ in either case will be the same.

Now, because the distribution is continuous, you have that

$0.17=\mathbb P(0$

The mean for the standard normal distribution is $0$ , and because the distribution is symmetric about its mean, it follows that $\mathbb P(Z$ .

$0.17=\mathbb P(Z$

You can consult a $z$ score table to find the corresponding score for this probability. It turns out to be $z\approx0.4399$ .